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andrezito [222]
3 years ago
9

the larger of two number is 15 more than three times the smaller number. If the sum of the two numbers is 63, find tge numbers.

Mathematics
2 answers:
irakobra [83]3 years ago
6 0
X is the smaller number. 3x + 15 is the larger number. So x + 3x + 15 = 63. 4x + 15 = 63.
4x = 48. x = 12. (Smaller number) The larger 36 + 15 or 51.
Marianna [84]3 years ago
3 0
To solve this we will write an equation to describe the situation.
(For some fun let us use (Apple) to represent the smaller number, and (Pineapple) for the big number)

Basically what the question is telling us is:
 (apple) + (pineapple)  = 63

Now we need to know what and (apple) and (pineapple)   are.
(pineapple) = 15 more than 3x the smaller number = 3(apple)   +  15
(apple): nothing special to do to it so it is just (apple)

Now we can replace (pineapple)  with what we calculated above. (pineapple) = 3(apple)  +  15

This means (apple)  + (3(apple)  + 15) = 63

  (apple) + 3(apples)  is simply 4(apples) 

So, the equation is now 4(apples)
  + 15 = 63

Now lets solve for (apple)  .
4(apple)  + 15 = 63
4(apple)  = 63 - 15
4(apple) = 48
(apple)= 48 ÷ 4

(apple) = 12
Voila! Now we know what (apple) is, but we still need to find (pineapple)  .

Remember how  (pineapple)  = 3(apple)   +  15 ?
We know (apple)  = 12 so plug in 12 for (apple)  to find out what (pineapple)   is.

  (pineapple) = 3(12) + 15
  (pineapple) = 36 + 15
  (pineapple) = 51

Now just to check: (apple)   +  (pineapple) should equal 63
Does 12 + 51 = 63? YES! so this answer is correct.

The two numbers you are looking for are:
apple = smaller number = 12
pineapple = bigger number = 51



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Answer:

These problems are an example of equations with two unknowns. The way these equations are solved is that we write these equations one under the another.

If both equations have, such is the case here, same parts, we can simply cancel the same parts out and subtract the rest of equatuons. That way, we are left with only one unknown (the other one was eliminated), which makes it easy to solve.

After we have found the value of an unknown, we just plug it back into any of the starting equations and solve for the second unknown.

2. Adult ticket costs $12 and child ticket costs $14.

3. Adult ticket costs $10 and child ticket costs $5.

4. One daylily costs $9 and one bush of ornamental grass costs $2.

5. A van can carry 15 and a bus can carry 56 students.

Step-by-step explanation:

2. If we mark the price of one adult ticket with x and the price of one child ticket with y, we get that:

- first day: 7x + 12y = $252

- second day: 7x + 10y = $224

Now, we can make a system:

7x + 12y = 252

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We can now subtract these two equations and 7x will cancel out, so we get:

12y - 10y = 252 - 224

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Now, we can plug the value of y into any of the two equations:

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7x + 140 = 224

7x = 84

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3. Similarly, if we mark the price of one adult ticket with x and the price of one child tickey with y, we'll get a system:

x + 12y = 70

x + 9y = 55

Again, if we subtract these two, x will cancel out, so we have:

12y - 9y = 70 - 55

3y = 15

y = 5

Now, we plug the value of y into any of the two equations, and we get:

x + 9y = 55

x + 45 = 55

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4. Using the same principle, we can mark the price of one daylily with x and the price of one bunch of ornamental grass with y, we'll get a system:

12x + 11y = 130

12x + 12y = 132

Again, we subtract so that 12x cancel out and we get:

11y - 12y = 130 - 132

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If we get minuses on both sides, we can simply multiply both sides with -1 and we get:

y = 2

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As you've probably already noticed the pattern, we subtract equations and cancel 2x out to get:

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Method Use : Completing the square

-------------------------------
Answer: x = 9 or x = -1
-------------------------------

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