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mina [271]
3 years ago
13

41) 124 students went on a field trip. Three

Mathematics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

40 students on each bus

Step-by-step explanation:

If you subtract the 4 students that traveled by car from the total 124 students, you are left with 120 students riding the 3 buses. Then, you would divide 120 by 3. (120 students divided by 3 buses.)  120/3 = 40

Helga [31]3 years ago
7 0

Start with what the question "how many students were in each bus?". We dont know that value, so let's call that x for now.

x = number of students in 1 bus

We have 3 buses, so we represent that by 3x

3x = number of students in 3 buses

Then add on 4 to represent the number of students who took a car

3x+4 = total number of students

3x+4 = 124 is the equation we need to solve

------------

Let's solve for x

3x+4 = 124

3x+4-4 = 124-4  .... subtract 4 from both sides

3x = 120

3x/3 = 120/3 .... divide both sides by 3

x = 40 is the number of students in one bus

------------

Each bus holds 40 students

3 buses hold 3*x = 3*40 = 120 students

adding on those 4 additional students gets us to 120+4 = 124 so we've confirmed the answer.

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Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.
valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}

On the other hand, the distance form P to B is equal to d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

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Take the square in both sides of this equation to get

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You can simplify using difference of squares and multiplying like this:

(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0

14x-10y-8z+36=0

which is the equation of a plane.

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4 years ago
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