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schepotkina [342]
3 years ago
7

How to find the inverse of this function

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0
F^-1(x) = -4 + 2x
Interchange the variables, then solve for y.
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Please help me with this !
lakkis [162]

Answer: x intercept : (3/2 , 0)

y intercept: (0, -2)

Step-by-step explanation:

6 0
3 years ago
Find the standard form polynomial that represents this product. (6 - y - 4y^2)(-5 + 7y^2)​
Tema [17]

Answer:

  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

Step-by-step explanation:

<u>Opening the parenthesis and simplifying by combining like terms:</u>

  • (6 - y - 4y^2)(-5 + 7y^2)​  =
  • 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
  • -30 + 42y^2  + 5y - 7y^3 +20y^2 -28y^4 =
  • -28y^4 - 7y^3 + 62y^2 + 5y - 30

5 0
4 years ago
More math help please!
Nata [24]
AS we know that:

V=SA*h

And we have the volume and we can calculate the SA,,,

So that, we can conclude:
h= \frac{V}{SA} = \frac{323.5}{\pi (7)^2} =2.1015~~in

Are you satisfied?




3 0
3 years ago
Read 2 more answers
Help please. Geometry.
Luda [366]

Answer:

Trapezoid i think

7 0
3 years ago
Read 2 more answers
Give the largest interval over which the general solution is defined. (Think about the implications of any singular points. Ente
Leto [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   No singular point due to the exponent in the solution

    The interval is   -\infty

b

   NONE

Step-by-step explanation:

From the question we are told that

     \frac{dy}{dx} =  9y

The generally solution is mathematically represented as

         \frac{dy }{dx}  =  9y

=>       \frac{dy}{y}  =  9dx

integrating both sides  

         \int\limits  {\frac{ dy}{y} } \,  = \int\limits  {9} \, dx

  =>   lny = 9x + c

 =>   y =  e^{9x +c }

 =>    y =  e^{9x} e^{c}

Here e^c  =  C

=>     y = C  e^{9x}

From the above equation we see that the domain for x has no singular point the interval is

       -\infty

Also there is no transient term in the general solution obtained because as  x \to \infty there no case where y \to 0

7 0
3 years ago
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