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3 years ago

How to find the inverse of this function

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

4 0

F^-1(x) = -4 + 2x
Interchange the variables, then solve for y.

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Use completing the aquare to solve for x in the equation (x+7)(x-9)=25

Tema [17]

Answer:

x = 1 + sqrt(89) or x = 1 - sqrt(89)

Step-by-step explanation:

Solve for x:

(x - 9) (x + 7) = 25

Expand out terms of the left hand side:

x^2 - 2 x - 63 = 25

Add 63 to both sides:

x^2 - 2 x = 88

Add 1 to both sides:

x^2 - 2 x + 1 = 89

Write the left hand side as a square:

(x - 1)^2 = 89

Take the square root of both sides:

x - 1 = sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

x = 1 + sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

Answer: x = 1 + sqrt(89) or x = 1 - sqrt(89)

7 0

3 years ago

angle a and angle b are complementary angles. angle a measures 67 degrees. what is the measure of angle b?

allochka39001 [22]

The answer is 23 because they have to add up to 90 :) - beanz

6 0

3 years ago

3x - 3y = -3<br>2x - y = -5

Korolek [52]

For this case we must solve the following system of equations:

$3x-3y = -3\\2x-y = -5$

To solve we follow the steps below:

We multiply the second equation by -3:

$-6x + 3y = 15$

Thus, we have the equivalent system:

$3x-3y = -3\\-6x + 3y = 15$

We add the equations:

$3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4$

We look for the value of the variable "y":

$2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3$

Thus, the solution of the system is given by:

$(x, y): (- 4, -3)$

Answer:

$(x, y): (- 4, -3)$

4 0

3 years ago

Graph y=5/3x -9 ......

alisha [4.7K]

Put a point at -9 because that is the y-intercept.then from the point -9 count up 5 and count over 3.

4 0

3 years ago

Read 2 more answers

Write the equation of a line perpendicular to 5x – 4y = - 3 that passes through the point (-5,2).

kolezko [41]

Answer: 5y + 4x = - 10

Step-by-step explanation:

Two lines are said to be perpendicular if the product of their gradients = -1.

If the gradient of the first line is $m_{1}$ and the gradient of the second line is $m_{2}$ , if the lines are perpendicular, them

$m_{1}$ x $m_{2}$ = -1 , that is

$m_{1}$ = $\frac{-1}{m_{2} }$

The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.

The equation in slope -intercept form is given as :

y =mx + c , where m is the slope and c is the y - intercept.

Writing the equation in this form , we have

5x - 4y = + 3

4y = 5x -+3

y = 5x/4 + 3/4

comparing with the equation y = mx + c , then $m_{1}$ = 5/4

Which means that $m_{2}$ = -4/5 and the line passes through the point ( -5 , 2 ).

Using the equation of line in slope - point form to find the equation of the line;

y - $y_{1}$ = m ( x - $y_{1}$ )

y - 2 = -4/5 ( x +5)

5(y - 2 ) = -4 ( x + 5 )

5y - 10 = -4x - 20

5y + 4x = - 10

4 0

3 years ago