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aleksklad [387]
2 years ago
5

There were 18 students running in a race. How many different arrangements of first, second, and third place are possible?

Mathematics
1 answer:
swat322 years ago
8 0

Answer:

There are 18 choices for first place, 17 for second, and 16 for third.

Therefore, there are 18 x 17 x 16=4896

So there are 4,896 ways possible

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting your time and may God bless you:)

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3 years ago
Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how man
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Adrian can put a total of 1716 combinations in the player. 

The formula to be used is as follows:

total combinations = n!/[r! *(n-r)!]
n = number of disks available  = 13
r = number of disks that be held = 6

= 13! = (13• 12•11•10•9•8•7•6•5•4•3•2•1)/(6! <span>• 7!)
</span>=1716

Thank you for posting your question. Feel free to ask me more.



6 0
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