All categories

3 years ago

Match the table with the function that models the data

Mathematics

1 answer:

algol133 years ago

4 0

The answer will be y=x4, really because the x slot times 4 would equal to y, look at it like this. 1 times 4 equals 4, then 4 times 4 equals 16 and keep moving down the list, plus without x there will be no y to make a product.

You might be interested in

Please help It’s due at 11:59 it’s 9:29 right now!!

yan [13]

Step-by-step explanation:

8969kg/cm^3
20oz jar of$2.78

3 0

3 years ago

Which characteristics do the functions have in common?

m_a_m_a [10]

Answer:

Range, Maximum, and y-intercept

Step-by-step explanation:

Range is the y-values of the function. Each of these functions has a range of (-inf, 10].

The maximum is the largest y-value that is part of the range, which is 10 for both functions.

y-intercept is where the function crosses the y-axis which is 10 for both functions.

6 0

3 years ago

The average student loan debt for college graduates is $25,150.

Aleks04 [339]

Using the normal distribution, it is found that:

a) $X \approx N(25150, 12050)$

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 25150, \sigma = 12050$ .

Hence the distribution of X can be described as follows:

$X \approx N(25150, 12050)$

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{33950 - 25150}{12050}$

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14200 - 25150}{12050}$

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

$Z = \frac{X - \mu}{\sigma}$

$-0.127 = \frac{X - 25150}{12050}$