9514 1404 393
Answer:
- 9x -5y = 4 . . . . standard form
- 9x -5y -4 = 0 . . . . general form
- y -1 = 9/5(x -1) . . . . . point-slope form
Step-by-step explanation:
The intercepts are ...
x-intercept = -4/-9 = 4/9
y-intercept = -4/5
Knowing these intercepts means we can put the equation in intercept form.
x/(4/9) -y/(4/5) = 1
The fractional intercepts make graphing somewhat difficult. However, we observe that the sum of the x- and y-coefficients is equal to the constant:
-9 +5 = -4
This means the point (x, y) = (1, 1) is on the graph. Knowing a point, we can write several equations using that point.
We like a positive leading coefficient (as for standard or general form), so we can multiply the given equation by -1.
9x -5y = 4 . . . . . standard form equation
Adding -4, so f(x,y) = 0, puts this in general form.
9x -5y -4 = 0
We can eliminate the constant by translating a line from the origin to the point we know:
9(x -1) -5(y -1) = 0
This can be rearranged to the traditional point-slope form ...
y -1 = 9/5(x -1)
Yet another equation can be written that tells you the slope is the same everywhere:
(y -1)/(x -1) = 9/5
These are only a few of the many possible forms of a linear equation.
Answer:
A. △P'Q'R' does not equal △P''Q''R''.
B. Reflecting across UT would change the orientation of the figure.
C. The sequence does not include a reflection that exchanges U and S.
D. Rotating about point U is not a rigid motion because it changes the orientation of the figure.
E. Translating point R' to Q' is a non-invertible transformation because it changes the location of P'.
(D) Rotating about U is not a rigid motion because it changes the orientation of the figure. [I think D is an incorrect answer choice.]
Step-by-step explanation:
Proof No.1
Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R' about point U to get △P''Q''R''. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.
Proof No.2
Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R about point U to get △P''Q''R'' so that R''Q'' and UT coincide. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.
Answer:
r=0.5 or 1/2
Step-by-step explanation:
if you multiply 0.5 to each Xs you can find out why r is 0.5
Answer:
enuwrwrju2rjwr
Step-by-step explanation:
hea
ddke5jektkbt3rtketlnwtet
