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Vlada [557]
3 years ago
7

Determine whether each quadrilateral is a parallelogram rectangle rhombus and Dory Square list of all that apply.​

Mathematics
1 answer:
jeka943 years ago
3 0

Answer: see below

<u>Step-by-step explanation:</u>

(1)

  a)\quad EF = 3\sqrt2,\quad FG = 3\sqrt2,\quad GH = 3\sqrt2,\quad HE = 3\sqrt2

  b)   FH = 6, EG = 6

  c)   Square (which means it is also a rectangle and parallelogram)

(2)

  a)\quad m_{EF}=3,\quad m_{FG}=-\dfrac{1}{2},\quad m_{GH}=3,\quad m_{HE}=-\dfrac{1}{2}

  b)\quad \text{Midpoint}_{EG}=(4.5, 1.5),\quad \text{Midpoint}_{FH}=(4.5, 1.5)

  c)   Parallelogram

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The length of a solar car race track is supposed to be 4.8 meters.
snow_tiger [21]

Answer:

  -12.5%

Step-by-step explanation:

A percentage change is computed using ...

  percent change = ((new amount) -(original amount))/(original amount) × 100%

We want to find the percentage change from 4.8 m, so we have ...

  percent change = (4.2 -4.8)/4.8 × 100% = -.6/4.8×100% = -12.5%

The carpenter made the track 12.5% too short.

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3 years ago
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Harman [31]

Answer:

x > 3

Step-by-step explanation:

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4 0
3 years ago
Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.
Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

with partial derivatives (set to 0)

L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
L_z=5xy+2\lambda z=0
L_\lambda=x^2+y^2+z^2-1=0

We then observe that

xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2

So, ignoring the critical point we've already found at (0, 0, 0),


5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
5 0
3 years ago
What is (7-4i)+(-2+5i)
Alla [95]

Answer:

(7-4i)+(-2+5i) = 5 + i

Answer =  5 + i

Step-by-step explanation:

Group the real part and the imaginary part of the complex number

( 7 - 4i ) + (-2 + 5i )

= ( 7 - 2 ) + ( -4 + 5 ) i

Refine = 5 + i

5 0
3 years ago
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adelina 88 [10]

Answer:

109.6

Step-by-step explanation:

3 0
3 years ago
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