<h3><em><u>Answers With Steps:</u></em></h3><h3>Question 1:</h3>
For the first problem, understand that you are solving for the area of a circle. The equation for the area of a circle is pi r². By using the leash length as the radius (r), you can get the answer. (The leash length is 3 meters long.)
<em>Question 1 Steps:</em>
pi 3² ---> pi * 9 ---> ≈28.27
<em>Question 1 Answer:</em>
It would have about 28.27 meters² of playable space.
<h3>Question 2:</h3>
For the second problem, it would be much the same as to the first question. There is the same objective to find the area of the circle. Along with that, it gives us a length to work with. This time it is the sprinkler's reach, which would be the radius, or "r" in the equation.
<em>Question 2 Steps:</em>
pi 5² ---> pi * 25 ---> ≈78.54
<em>Question 2 Answer:</em>
The sprinkler would have about 78.54 feet² of space that it can reach.
Answer:
m=8+3n
Step-by-step explanation:
Move all terms that don't contain m to the right side and solve.
Hope this helps <3
Answer:A
Step-by-step explanation:
Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = <u><em>amount a Niffler can hold in their pouch</em></u>
So, X ~ Normal(
)
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 25 pounds
= standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P(
>
) = P(Z > 1.03) = 1 - P(Z
1.03)
= 1 - 0.8485 = 0.1515
<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>
<em />
Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.