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kodGreya [7K]
3 years ago
5

A 3.5ft by 5.5ft mirror is placed in a wooden frame. What is the area of the frame?

Mathematics
2 answers:
Bingel [31]3 years ago
7 0
3.5*5.5=19.25
The formula to find the area is the length times width
Thepotemich [5.8K]3 years ago
3 0

Answer:

19.25 ft^2

Step-by-step explanation:

According to the dimension we can assume the mirror is a rectangle. The area of a rectangle is the length timest he width. The length is 5.5ft and the width is 3.5ft.

=5.5\cdot{3.5}=19.25

The area of the mirror is 19.25 ft^2

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These Questions are confused me a lot help if you could I really appreciate it thank you
matrenka [14]
<h3><em><u>Answers With Steps:</u></em></h3><h3>Question 1:</h3>

For the first problem, understand that you are solving for the area of a circle. The equation for the area of a circle is pi r². By using the leash length as the radius (r), you can get the answer. (The leash length is 3 meters long.)

<em>Question 1 Steps:</em>

pi 3² --->  pi * 9 ---> ≈28.27

<em>Question 1 Answer:</em>

It would have about 28.27 meters² of playable space.

<h3>Question 2:</h3>

For the second problem, it would be much the same as to the first question. There is the same objective to find the area of the circle. Along with that, it gives us a length to work with. This time it is the sprinkler's reach, which would be the radius, or "r" in the equation.

<em>Question 2 Steps:</em>

pi 5² ---> pi * 25 ---> ≈78.54

<em>Question 2 Answer:</em>

The sprinkler would have about 78.54 feet² of space that it can reach.

4 0
4 years ago
2. 3m - 9n = 24 solve for m<br>​
PIT_PIT [208]

Answer:

m=8+3n

Step-by-step explanation:

Move all terms that don't contain m to the right side and solve.

Hope this helps <3

5 0
3 years ago
Work for determining system for log base radical 2 of e​
igomit [66]

Answer:

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7 0
3 years ago
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Answer:A

Step-by-step explanation:

4 0
3 years ago
A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou
Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = <u><em>amount a Niffler can hold in their pouch</em></u>

So, X ~ Normal(\mu=25,\sigma^{2} =6.8^{2})

The z score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 25 pounds

            \sigma = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

  P(X > 32 pounds) = P( \frac{X-\mu}{\sigma} > \frac{32-25}{6.8} ) = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                                                             = 1 - 0.8485 = 0.1515

<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>

<em />

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0
3 years ago
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