14x + 10y = 72
14x + 4y = 96
6y = -24
6 6
y = -4
14x + 10y = 72
14x + 10(-4) = 72
14x - 40 = 72
+ 40 + 40
14x = 112
14 14
x = 8
(x, y) = (8, -4)
Solution: The number of ways we can arrange 3 blue marbles if a set of 5 marbles is selected is:



Therefore, there are 10 ways we could arrange 3 blue marbles.
4/10 would be left you would make it a whole fraction at 10/10 then minus 4/10 and minus 2/10 that leaves 4/10 of cards. Hope this helps you out.
The last option all the way to the right