All categories

2 years ago

5.815 in mixed number

Mathematics

2 answers:

zhannawk [14.2K]2 years ago

8 0

The answer is 5 815
1000

gizmo_the_mogwai [7]2 years ago

3 0

5 163/200 is 5.815 in a mixed number

You might be interested in

The value of 46,395 in 4

Cerrena [4.2K]

The value of 4 is in the 10,000 place. :)

3 0

2 years ago

Read 2 more answers

Which ordered pair in the form (a, b) is a solution of this equation?

Evgen [1.6K]

3a - 4b = 21

check (-2 , -3)

3(-2) -4(-3) =21

-6 +12 = 21

6 does not = 21 so NO

check (0 , 7)

3(0) -4(7) =21

0-28=21

-28 does not equal 21 so NO

check (-3 , -2)

3(-3) -4(-2) =21

-9 +8 = 21

1 does not = 21 so NO

check (7 , 0)

3(7) -4(0) =21

21 = 21

Choice D

5 0

3 years ago

NEED HELP IMMEDIATELY Which expression is equivalent to one over four n − 16?

Gemiola [76]

B. 1/4(n - 64)

Multiplying n and -64 by 1/4 leaves you with 1/4n - 16, the original equation.

5 0

3 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

Which one of the following are the factors of m2-14m+48

Over [174]

D.(m-6)(m-8) is the answer

7 0

3 years ago