Question

A jury pool consists of 27 people, 12 men and 15 women. Compute the probability that a randomly selected jury of 12 people is all male.
I really need this in the form of a decimal if you can!

Answer 1

Answer:The probability of selecting 12 males is 7/ 1337220

Step-by-step explanation:

I searched it up and saw an answer not my work tho so here there brainly.com/question/17075596 for more information

Answer 2

Answer:  Approximately 0.00000005752462

There are seven "0"s between the decimal point and the "5".

Round that value however you need to.

If you need the exact answer as a fraction, then it would be $\frac{1}{17,383,860}$ and you may need to delete the commas if necessary.

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Explanation:

We use the nCr combination formula to determine how many ways there are to form a jury if we had n = 27 people and r = 12 slots.

$n C r = \frac{n!}{r!(n-r)!}\\\\27 C 12 = \frac{27!}{12!*(27-12)!}\\\\27 C 12 = \frac{27!}{12!*15!}\\\\27 C 12 = \frac{27*26*25*24*23*22*21*20*19*18*17*16*15!}{12!*15!}\\\\ 27 C 12 = \frac{27*26*25*24*23*22*21*20*19*18*17*16}{12!}\\\\ 27 C 12 = \frac{27*26*25*24*23*22*21*20*19*18*17*16}{12*11*10*9*8*7*6*5*4*3*2*1}\\\\27 C 12 = \frac{8,326,896,754,176,000}{479,001,600}\\\\ 27 C 12 = 17,383,860$

There are a little over 17 million ways to form the jury. This is where order doesn't matter because no juror outranks any other (and there aren't any special positions).

Since there are 12 men and 12 spots on the jury, there's only one way to have a jury of all men.

The probability of getting a jury of all men is roughly

$\frac{1}{17,383,860} \approx 0.00000005752462$

which is an incredibly small probability. There are seven "0"s between the decimal point and the "5"