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Vlad1618 [11]
3 years ago
5

32/20 fully reduced in prime numbers

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

8/5

Step-by-step explanation:

EL NUMERADOR Y EL DENONINADOR SE DIVIDEN AL MISMO TIEMPO

ENTRE LOS NÚMEROS PRIMOS EN ORDEN HASTA QUE YA NO PUEDAN

DIVIDIRSE.

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Sarah has a collection of nickels, dimes, and quarters worth $28.75. She has 10 more dimes than nickels and twice as many quarte
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Answer:

Step-by-step explanation:

Write an equation for each statement:

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"Sarah has a collection of nickels, dimes, and quarters worth $15.75."

.05n + .1d + .25q = 15.75

:

"She has 10 more dimes than nickels"

d = n + 10

:

"twice as many quarters as dimes."

q = 2d

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How many coins of each kind does she have?

:

Take the 2nd equation and arrange it so n is in terms of d also

n + 10 = d

n = (d - 10)

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In the 1st equation substitute (d-10) for n and 2d for q:

.05n + .1d + .25q = 15.75

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.05(d-10) + .1d + .25(2d) = 15.75

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.05d - .5 + .1d + .5d = 15.75

:

.65d - .5 = 15.75

:

.65d = 15.75 + .5

:

.65d = 16.25

:

d = 16.25/.65

:

d = 25 dimes

:

Remember the statement "twice as many quarters as dimes."

q = 2(25)

q = 50 quarters

:

The statement "She has 10 more dimes than nickels"

n = 25 - 10

n - 15 nickels

:

Check our solutions

.05(15) + .1(25) + .25(50) =

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Step-by-step explanation:

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