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Vlad1618 [11]
3 years ago
5

32/20 fully reduced in prime numbers

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

8/5

Step-by-step explanation:

EL NUMERADOR Y EL DENONINADOR SE DIVIDEN AL MISMO TIEMPO

ENTRE LOS NÚMEROS PRIMOS EN ORDEN HASTA QUE YA NO PUEDAN

DIVIDIRSE.

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Solve the simultaneous equation x^2-4y^2=9 and x+2y=1​
Salsk061 [2.6K]

Answer:

x=5,y=-2

Step-by-step explanation:

8 0
3 years ago
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Cw 10.5 10.5 V. W<br> A great
Semmy [17]

Answer:

Refer to step-by-step.

Step-by-step explanation:

12.  x = 28

BC = x

AB = 96

AC = 100

We use the Pythagorean theorem to find the value of x.

a² + b² = c²

x² + 96² = 100²

x² + 9216 = 10000

x² = 10000-9216

x² = 784

√x² = √784

x = 28

13. x = 64

a² + b² = c²

48² + x² = 80²

2304 + x² = 6400

x² = 6400 - 2304

x² = 4096

√x² = √4096

x = 64

14. YES and 25 = 25

a² + b² = c²

3² + 4² = 5²

9 + 16 = 25

25 = 25

So this means that AB is tangent to the circle.

15. NO and 45 ≠ 49

a² + b² = c²

3² + 6² = 7²

9 + 36 = 49

45 = 49

So this means the AB is not tangent to the circle.

16. x = 4.5 and P = 52

To find the value of x, we need to determine the value of our hypotenuse.

QU is congruent to QT, therefore, QT = 4

UR is congruent with SR, therefore, UR = 13

PS is congruent to AB, therefore:

2x = 9

Divide both sides by 2

x = 4.5

The perimeter of a triangle is:

P = a + b + c

a = 9 + 4 or 13

b = 2(4.5) + 13 or 22

c = 4 + 13 or 17

P = 13 + 22 + 17

P = 52

17. x = 13 and P = 72

TJ is congruent to UJ, therefore, TJ = 13

x = 13

The perimeter of a parallelogram is:

P = 2(a+b)

a = HR + RK

b = KU + UJ

a = 13 + 5 or 18

b = 5 + 13 or 18

P = 2(18 + 18)

P = 2(36)

P = 72

18. x = 8 and P = 80

We know that part of the whole of 26 is 18 because one side is congruent to 18.

to find the value of the other half, we simply subtract 18 from 26.

26 - 18 = 8

x is congruent to 8, therefore x = 8

The line segment 14 is congruent to the opposite segment of x, therefore making the value 14.

So then we have:

a = 8 + 14 or 22

b = 26

c = 18 + 14 or 32

P = a + b + c

P = 22 + 26 + 32

P = 80

19. x = 6 and P = 52

Now we have the case of x + 2 is congruent to 8.

x + 2 = 8

Combine like terms.

x = 8 - 2

x = 6

Now that we have the value of x, we can simply look for the value of the line segment attached to it.

4 is congruent to the line segment attached to x + 2, therefore the value is 4.

To find the perimeter we have to add all sides together.

P = (8+5)+(5+9)+(9+4)+(8+4)

P = 52

20. x = 5, y = 2, z =10, and P = 68

Let's take this one step at a time.

First we look for x.

2x + 2 = 3x - 3

Combine like terms.

2x - 3x = -3 - 2

-x = -5

Divide both sides by -1.

x = 5

Now let's get the value of y.

5y - 2 = 3y + 2

Combine like terms.

5y - 3y = 2 + 2

2y = 4

Divide both sides by 2.

y = 2

Now let's look for z.

34 - 2z = z + 4

Combine like terms.

-2z - z = 4 - 34

-3z = -30

Divide both sides by -3.

z = 10

Now that we have the values of x, y, and z. We can substitute them to find the values of our segments.

2x + 2

2(5) + 2 = 12

3x - 3

3(5)-3 = 12

5y - 2

5(2) - 2 = 8

3y + 2

3(2) + 2 = 8

z + 4

10 + 4 = 14

34 - 2z

34 - 2(10)

34 - 20 = 14

Now that we have our values let's look for our perimeter.

P = a + b + c

P = (12 + 8) + (12 + 14) + (14 + 8)

P = 20 + 26 + 22

P = 68

4 0
3 years ago
I need help with this
Sloan [31]
That equals 27 hope this helps
3 0
3 years ago
The perimeter of a rectangle is 150 cm. the length is 4 cm greater than the width find the width and length
Fudgin [204]

Let's call the width of our rectangle w and the length l. We can say l = w + 4, since the length is equal to 4 cm greater than the width.


Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or P = 2l + 2w. To solve this problem, we can substitute in the information we know, as shown below:

150 = 2(w + 4) + 2w

150 = 4w + 8

142 = 4w

w = \frac{71}{2}


Now, we can substitute in the width we found into the formula for length, which is l = w + 4:

l = \frac{71}{2} + 4

l = \frac{79}{2}


The width of our rectangle is \boxed{\frac{71}{2} \,\, \textrm{cm}} cm and the length of our rectangle is \boxed{\frac{79}{2} \,\, \textrm{cm}}

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3 years ago
jaime en un joven que vive en puyo con su padre. A jaime le gusta cosechar chonta con su padre los sabados en la mañana jaime ha
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0.267 es la respuesta redondeada a la milésima más cercana

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