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2 years ago

PLS HELP ME I WILL MARK!!!!~ don't need to show work

Mathematics

2 answers:

Monica [59]2 years ago

8 0

Answer:

The answer is: 2x+1f(x)=

Step-by-step explanation:

The standard form for linear equations in two variables is Ax+By=C. For example, 2x+3y=5 is a linear equation in standard form. When an equation is given in this form, it's pretty easy to find both intercepts (x and y). This form is also very useful when solving systems of two linear equations.

Sauron [17]2 years ago

6 0

I’m not so sure, but I think it might be:
f(x)=x-1
Sorry if wrong

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Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I':

SVETLANKA909090 [29]

Answer:

(x, y)→(x − 8, y − 7)

Step-by-step explanation:

If we take the hexagon DEFGHI coordinates and apply the rule (x, y)→(x − 8, y − 7) we get:

D (2, 5) → (2 - 8, 5 - 7) = (-6, -2) which corresponds to point D'

E (5, 5) → (5 - 8, 5 - 7) = (-3, -2) which corresponds to point E'

F (6, 3) → (6 - 8, 3 - 7) = (-2, -4) which corresponds to point F'

G (5, 1) → (5 - 8, 1 - 7) = (-3, -6) which corresponds to point G'

H (2, 1) → (2 - 8, 1 - 7) = (-6, -6) which corresponds to point H'

I (1, 3) → (1 - 8, 3 - 7) = (-7, -4) which corresponds to point I'

6 0

2 years ago

Read 2 more answers

Find the sum<br> 10 + 8 + 0.6 + 0.04

Fudgin [204]

10 + 8 + 0.6 + 0.04 = 18.64

7 0

2 years ago

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Checking account A charged a monthly fee of $5 and a per-check fee of $0.25, and checking account B charged a monthly fee of $6

Genrish500 [490]

First we need to know both the formula of A and B.

The formula of A is
C = 5 + 0.25p
with C representing total cost and p representing the amount of checks.

The formula of B is
C = 6 + 0.15p
with C representing total cost and p representing the amount of checks.

To find the point where A and B cost the same, we solve the following equation:
5 + 0.25p = 6 + 0.15p

Collecting terms gives us
-1 = -0.1p

Now we have to divide by -0.1 and we get.
10 = p
p = 10

So our answer: after 10 checks both accounts cost the same amount of money. Answer A.

7 0

2 years ago

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

5 0

3 years ago

While traveling to Europe, Phelan exchanged 250 US dollars for euros. He spent 150 euros on his trip. After returning to the Uni

Anettt [7]

Since the exchange rate of euro to USD right now is 1:1.11, therefore he spent 150x1.11=166.5 USD. Therefore, he has 250-166.5=83.5 USD left(assuming the exchange rate is the same, 1.17).

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3 years ago

Read 2 more answers