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3 years ago

Guys please help me to do these!!!! im tryin’ my best but it’s so hard

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

Answer:

Step-by-step explanation:

∠ACB=6 x°

∠DCE=30°

6x=30°-----------------divide both sides by 6

x=30°/6= 5°

∠BCE=180°-30°=150°----------------sum of angles on a straight line

∠ABD=(4+5x)°

∠CBD=(x+2)°

(4+5x)°+(x+2)°=180°-----------sum of angles on a straight line

4+5x+x+2=180°----------------collect like terms

6x+6=180°

6x=180°-6°

6x=174°------------divide by 6 both sides

x=174°÷6= 29°

∠ABD=4+5x=4+(5*29)= 4+145=149°

∠CBD= x+2=29°+2°=31°

BE bisects ∠ABE=(3x+1)°

m∠DBA=(8x-14)°

1/2 (m∠DBA)° = m∠ABE

1/2(8x-14)°=(3x+1)°

(4x-7)°=(3x+1)°

4x-7=3x+1

4x-3x=7+1-------------collecting like terms

x=8°

m∠ABE=(3x+1)°=(3*8+1)=24+1=25°

m∠DBA=(8x-14)°= (8*8-14)°=(64-14)=50°

∠ADE=∠CDG

50+3x-y=x+2x-16------------collect like terms

50+16-y=x+2x-3x

66-y=3x-3x

66°=y

∠ADC +∠ADB+∠BDE

90°+50°+(3x-y)°=180°

140°+(3x-y)°=180°

3x-66°=180°-140°

3x=40°+66°

3x=106°-----------divide both sides by 3

x=106°÷3= 35.33°

∠FDG=(2x-16)°= (2×35.33° - 16° )= 54.67°

∠BDE = (3x-y)°= (3×35.33°-66°)= 105.99-66=39.99°

∠ABD+∠DBC=90°

(6x+4)°+32°=90°

(6x+4)°=90°-32°

6x+4=58°

6x=58°-4°

6x=54°

x=54°÷6=9°

∠ABD= (6x+4)°+32°

∠ABD= (6×9 +4)°+32°

∠ABD= (54°+4°) + 32°

∠ABD=58°+32°=90°

∠AED=∠CEB

(3x+5)°=(4y-15)°------------------form equation of equality

3x+5=4y-15

5+15=4y-3x

20=4y-3x------------------------------(1)

∠AEC=∠DEB

(y+20)°=(x+15)°

y+20=x+15

20-15=x-y

5°=x-y

5+y=x----------------------------(2)

Use equation (2) in equation (1)

20=4y-3x

20=4y-3(5+y)

20=4y-15-3y

20+15=4y-3y

35°=y

Solve for x

x=5+y=5°+35°=40°

∠AED=(3x+5)°=(3×40 +5 )=120+5=125°

∠AEC= (y+20)°= 35° + 20° =55°

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3 0

2 years ago

Using the order of operations, what is the last calculation that should be done to evaluate

mel-nik [20]

200-(-2) is actually 200-1(-2)

So thats multiplication

Then its 200+2

So addition is the last calculation to be done.

7 0

3 years ago

Read 2 more answers

PLZ HELP!!!!!!!!!!!!!!!!!!

Inessa05 [86]

Answer:

D.) If soccer balls are sold for $2.05 or $14.61 each, the store will break even but will not make a profit.

Step-by-step explanation:

Let us assume x = selling price of each soccer ball

y = daily profit earned from selling of soccer balls

Given that

Y= $-6x^2+100x-180$

where,

a = -6

b = 100

c = -180

Now we have to applied the formula which is as follows

x $= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

$= \frac{-100\pm\sqrt{100^2-4\times -6\times -180}}{2\times -6}$$

$= \frac{-100\pm\sqrt{10,000 - 4,320}}{-12}$$

$= \frac{-100\pm\sqrt{5.680}}{-12}$$

$= \frac{-100 + 75.3658}{-12}$$

$= \frac{24.6342}{-12}$

x^1 = -2.05285

Now

x^2 $= \frac{-100 - 75.3658}{-12}$$

$= \frac{- 175.3658}{-12}$

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Based on this the option D is most appropriate as per the given situation

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2 years ago

Read 2 more answers

Use the alternative form of the dot product to find u · v.

vodka [1.7K]

Answer:

Step-by-step explanation:

u = 45

v = 30

Angle between them, θ = 5π / 6 = 150°

(a) The formula for the dot product is given by

$\overrightarrow{u}.\overrightarrow{v}= u v Cos\theta$

$\overrightarrow{u}.\overrightarrow{v}= 45 \times 30 \times Cos150$

$\overrightarrow{u}.\overrightarrow{v}= -1169.13$

(b) $\overrightarrow{u}=Cos\frac{\pi }{3}\widehat{i}+Sin\frac{\pi }{3}\widehat{j}$

$\overrightarrow{u}=0.5\widehat{i}+0.866\widehat{j}$

$\overrightarrow{v}=Cos\frac{2\pi }{3}\widehat{i}+Sin\frac{2\pi }{3}\widehat{j}$

$\overrightarrow{v}=-0.707\widehat{i}+0.707\widehat{j}$

Let the angle between them is θ

The formula in terms of the dot product is given by

$Cos\theta =\frac{\overrightarrow{u}.\overrightarrow{v}}{u v}$

$u=\sqrt{0.5^{2}+0.866^{2}}=1$

$v=\sqrt{-0.707^{2}+0.707^{2}}=1$

$Cos\theta =\frac{0.5 \times (-0.707) + 0.866 \times 0.707)}{1\times 1}$

$Cos\theta=0.2587$

θ = 75°

$u=\sqrt{1^{2}+4^{2}+8^{2}}=9$

$Cos\alpha =\frac{1}{9}$

$Cos\beta =\frac{4}{9}$

$Cos\gamma =\frac{8}{9}$

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3 years ago

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IrinaK [193]

Answer:

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Step-by-step explanation:

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