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3 years ago

Evaluate - x - 4 when x = - 7 and y=5

Mathematics

1 answer:

shusha [124]3 years ago

7 0

Answer:

khan academy

Step-by-step explanation:

https://www.khanacademy.org/math/in-in-grade-9-ncert/xfd53e0255cd302f8:in-in-chapter-4-linear-equations-in-two-variables/xfd53e0255cd302f8:in-in-graph-of-a-linear-equation-in-two-variables/v/graphs-of-linear-equations

hope this helps

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Anita works for a dog-walking service. She earns a one-time fee of $10 plus an additional $2 for each dog she walks. If Anita wa

ahrayia [7]

40=10+2x where x is the number of dogs.
30=2x
x=15
Therefore she must walk 15 dogs

Hope this helps :)

6 0

3 years ago

The cost to rent an instrument is $65 for the first month it costs $30 for each additional month,x, that the instrument is rente

yawa3891 [41]

Answer:

65+30x

Step-by-step explanation:

You forgot to give the choices.

But, I would think it's 65+30x=

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3 years ago

A flock of geese is flying north for the summer while a bird watcher is observing. He notices that they are flying in the shape

nata0808 [166]

Answer:

y = -¼│x − 5│+ 3

Step-by-step explanation:

y = a│x − h│+ k

(h, k) is the vertex of the absolute value graph. In this case, it's (5, 3).

y = a│x − 5│+ 3

One point on the graph is (1, 2). Plug in to find the value of a.

2 = a│1 − 5│+ 3

2 = 4a + 3

a = -¼

Therefore, the graph is:

y = -¼│x − 5│+ 3

4 0

3 years ago

On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)

goldfiish [28.3K]

Answer:

f(x) > 0 over the interval $(-\infty,-4)$

Step-by-step explanation:

If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from $- \infty$ , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from $- \infty$ to -3, since between the values -4 and -3 the function adopts negative values.

6 0

3 years ago

Read 2 more answers

Consider the line: y= -7/2x-7 find the equation of the line that is perpendicular and parallel to this line that passes through

saveliy_v [14]

Answer:

Step-by-step explanation:

(5)=-7/2(-2)-7

5=7-7

3 0

3 years ago