You can solve this easily by using Pascal's Triangle (look that up if need be).
Here are the first four rows of P. Triangle:
1
1 1
1 2 1
1 3 3 1
example: expand (a+b)^3.
Look at the 4th row. Borrow and use those coefficients:
1a^3 + 3 a^2b + 3ab^2 + b^3
Now expand (4x+3y)^3:
1(4x)^3 + 3(4x)^2(3y) + 3(4x)*(3y)^2 + (3y)^3
Look at the 2nd term (above):
3(4x)^2(3y) can be re-written as 144x^2y.
The coeff of the 2nd term is 144. Note that (4)^2 = 16
Cm wait what is the question
Answer:
c
Step-by-step explanation:
just cause
Answer: I know about this question I’m struggling on it..
Step-by-step explanation:
In this circle we have major arc RQ which is the really big one measuring 40x, and we have minor arc RQ, which is what we are looking for. Minor arc RQ is double the measure of the angle that intercepts it. That means that minor arc RQ is 2(12x-12), which is 24x - 24. The measure of the outside of any circle will always and forever be 360 degrees; therefore, 40x + 24x - 24 = 360. Combining like terms gives us 64x = 384 and x = 6. Now sub in that 6 for the x in the angle 12x - 12 to get that that angle measures 12(6)-12 = 60. Again, the angle is half the measure of the arc it intercepts, so minor arc RQ is 120 degrees, third choice down.
