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miss Akunina [59]
4 years ago
6

How do you do this? It's due tomorrow

Mathematics
2 answers:
Korvikt [17]4 years ago
4 0
Lets think they have cards,  Alex = x , Gil = y and Meg = z. Then,
x+y+z = 740

Alex had 20 fewer cards than Gil. So,
x+20 = y

Alex had 120 fewer cards than Meg. So,
x+120 = z

 x+(x+20)+(x+120) = 740
3x + 140 = 740
x= 200

y= 220
z= 320

<span>So Alex had 200 cards, Gil had 220 cards and Meg had 340 cards</span>
belka [17]4 years ago
3 0
A=alex
g=gil
m=meg

they share 740 cards
a+g+m=740

alex has 20 fewer than gil and 120 fewer than meg (women rights?)
a=g-20 and a=m-120

so

a=g-20 and a=m-120
add 20 to bot sides for the left one and 120 to boht isdes for the right one
a+20=g and a+120=m

subsitute a+20=g for g and a+120=m for m

a+g+m=740
a+a+20+a+120=740
3a+140=740
minus 140 both sides
3a=600
divide both sies by 3
a=200

alex has 200 cards
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Can someone help me with this? Please this would mean so much.
Paha777 [63]

Answers:

x = angle MLN = 35 degrees

angle FLJ = 55 degrees

=================================================

Explanation:

This problem is fairly tricky if you're not sure what to look for. A slight clue is that they've marked a red point that strangely doesn't have a label on it. It's a fairly small point but it's definitely there if you look closely. While this point's location isn't exactly what we want, we're fairly close. Start at point L and draw a ray through the center point P. Ray LP will intersect the circle at point A, as shown in the diagram below.

From here, draw segments FA and MA. Now notice that inscribed angle LMF = 55 and inscribed angle FAL both subtend the same arc. The term "subtend" basically means "cut off". This arc that the inscribed angles subtend is minor arc FL. A minor arc is where you travel the shorter path around the circle, which indicates its measure is less than 180 degrees.

Since inscribed angles LMF and FAL subtend the same minor arc, this makes the inscribed angles to be congruent.

In short: angle FAL is 55 degrees

----------------------

Segment LA goes through the center P. Through Thales theorem, we know that inscribed angle LFA is 90 degrees. Consequently, we can determine that inscribed angle FLA is 90-55 = 35 degrees.

Segment JL is tangent to the circle, meaning that angle ALJ is 90 degrees. So angle FLJ is 90-35 = 55 degrees.

It's not a coincidence that angle FLJ, angle FAL, and angle LMF are the same measure.

----------------------

We found that angle FAL was 55 degrees. Applying Thales theorem again shows that angle MAF is 90 degrees. Therefore, angle LAM is 90-55 = 35 degrees.

Focus now on triangle LMA. This is also a right triangle (Thales Theorem). The upper acute angle we found was angle LAM = 35, so the lower acute angle is ALM = 55.

Then we can find angle MLN = (angle ALN) - (angle ALM) = 90 - 55 = 35

In short, angle MLN = 35 degrees

Similar to the previous section, it is not a coincidence that angles LFM, LAM and MLN are the same measure.

------------------------

As an alternative, since we know angle FLJ = 55, and angle FLM is 90 degrees, this means...

(angle FLJ)+(angle FLM) + (angle MLN) = 180

55 + 90 + angle MLN = 180

145 + angle MLN = 180

angle MLN = 180 - 145

angle MLN = 35 degrees

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To find the length of the diagonal, we need to calculate the length of the base first and then use the value to calculate the diagonal since we are given the value of height of the triangle.

<h3>Pythagorean Theorem</h3>

This theorem is used to find the missing side of a right angle triangle given that we have the length of two sides.

To calculate the base of the triangle, let's use Pythagorean theorem here

x^2 = y^2 + z^2\\x^2 = 2^2 + 3^2\\x^2 = 4 + 9 \\x^2 = 13\\x = \sqrt{13} \\x = 3.61

Having the length of the base, let's consider the height of the triangle which is 6 and substitute the values.

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From the calculations above, the values of the triangle are

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Learn more on pythagorean theorem here;

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