How do you do this? It's due tomorrow
2 answers:
Lets think they have cards, Alex = x , Gil = y and Meg = z. Then, x+y+z = 740 Alex had 20 fewer cards than Gil. So, x+20 = y Alex had 120 fewer cards than Meg. So, x+120 = z x+(x+20)+(x+120) = 740 3x + 140 = 740 x= 200 y= 220 z= 320 <span>So Alex had 200 cards, Gil had 220 cards and Meg had 340 cards</span>
A=alex g=gil m=meg they share 740 cards a+g+m=740 alex has 20 fewer than gil and 120 fewer than meg (women rights?) a=g-20 and a=m-120 so a=g-20 and a=m-120 add 20 to bot sides for the left one and 120 to boht isdes for the right one a+20=g and a+120=m subsitute a+20=g for g and a+120=m for m a+g+m=740 a+a+20+a+120=740 3a+140=740 minus 140 both sides 3a=600 divide both sies by 3 a=200 alex has 200 cards
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