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Soloha48 [4]
3 years ago
5

Which equations could be used to solve for the

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

Answer: A,E

Explanation: i just sacrificed my answer to find the right answer

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A ray is a part of a line.
amm1812

Answer:

A ray is a part of a line.

Step-by-step explanation:

yes

5 0
3 years ago
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true or false? The sum of the difference is not always zero for any distribution consisting of n observations
mezya [45]

Answer:

i believe the answer is false !

Step-by-step explanation:

3 0
2 years ago
Factor completely 3x2 + x + 7.
Step2247 [10]

Answer:

-1

Step-by-step explanation:

3 • 7 = 21

Find two factors of 21 whose sum equals the coefficient of the middle term, which is -1 .

-21 + -1 = -22

-1 + -21 = -22

1 + 21 = 22

21 + 1 = 22

4 0
3 years ago
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(problem 6.13 page 97) Consider a population in which 80% of males and 60% of females are employed. In this population, 55% of i
svp [43]

Answer:

There is a 50.77% probability that no more than one of those chosen is not employed.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will be employed, or they will not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

We have these following percentages:

55% of the individuals are female.

So 45% of the individuals are male.

80% of males are employed. So 20% of males are unemployed.

60% of females are employed. So 40% of females are unemployed.

If I pick five persons at random from this population, what is the probability that no more than one of those chosen is not employed?

Using the binomial distribution, p is the probability that a person is unemployed. 40% of the females and 20% of the males are unemployed. The population is 55% females and 45% males. So

p = 0.4*0.55 + 0.2*0.45 = 0.31

There are five persons, so n = 5

What is the probability that no more than one of those chosen is not employed?

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.31)^{0}.(0.69)^{5} = 0.1564

P(X = 1) = C_{5,1}.(0.31)^{1}.(0.69)^{4} = 0.3513

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.1564 + 0.3513 = 0.5077

There is a 50.77% probability that no more than one of those chosen is not employed.

7 0
3 years ago
There are 6 squares and 2 circles. What is the simplest ratio of circles to total shapes?
Sunny_sXe [5.5K]

Add to find the total number of shapes.

6 + 2 = 8

Circles to total amount of shapes -> 2:8

Divide 2 to both sides.

2/2:8/2

1:4

Therefore, the answer is 1:4

Best of Luck!

4 0
3 years ago
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