All categories

3 years ago

This graph of a function is a translation of y = 2/x . What is an equation for the function?

Mathematics

2 answers:

MArishka [77]3 years ago

6 0

Answer:

The correct option is C) $y=\frac{2}{x-3}-6$

Step-by-step explanation:

Consider the provided information.

Transformation:

The graph of parent function f(x) move up b unit for f(x)+b.

The graph of parent function f(x) move down b unit for f(x)-b.

The graph of parent function f(x) move left b unit for f(x+b).

The graph of parent function f(x) move right b unit for f(x-b).

Since, the graph of the parent function moves down, Therefore Option Option B and D are incorrect.

Here, we can observe that vertical asymptote shifted from x = 0 to x = 3.

Horizontal Shift: Right 3 Units

Vertical Shift: Down 6 Units

Therefore, the correct option is C) $y=\frac{2}{x-3}-6$

Sphinxa [80]3 years ago

5 0

Answer: The answer is C, the rest of the answers are

1:B

2:C

3:A its a graph

4:C y=2/x-3 -6

5:D19, as of 2019

Step-by-step explanation:

You might be interested in

Find the inverse of f(x)=1/(x^3)

Pepsi [2]

Answer:

Step-by-step explanation:

y $f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}$

4 0

3 years ago

Make x the subject of y=alog(5x)

Bond [772]

Answer:

x = 0.2(10^y/a).

Step-by-step explanation:

y = alog(5x)

y = log(5x)^a) By the definition of a log:

(5x)^a = 10^y

5x = (10^y) ^ 1/a

x = 0.2(10^y/a)

4 0

2 years ago

Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling

sergeinik [125]

Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are $2^{30}$ lilypads on the 30th, and $2^{29}$ lilypads on the 29th. This can be deduced multiplying succesively by 2.