1. Let a and b be coefficients such that

Combining the fractions on the right gives



so that

2. a. The given ODE is separable as

Using the result of part (1), integrating both sides gives

Given that y = 1 when x = 1, we find

so the particular solution to the ODE is

We can solve this explicitly for y :


![\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|](https://tex.z-dn.net/?f=%5Cln%7Cy%7C%20%3D%20%5Cln%5Cleft%7C%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%5Cright%7C)
![\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%7D)
2. b. When x = 9, we get
![y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B45%7D%7B21%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D7%7D%20%5Capprox%20%5Cboxed%7B1.29%7D)
Answer:
B. 6.3%
Step-by-step explanation:
For each time that the coin is tosse, there are only two possible outcomes. Either it comes up tails, or it does not. The probability of coming up tails on a toss is independent of any other toss. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
Fair coin:
Equally as likely to come up heads or tails, so 
Probability that the first tails comes up on the 4th flip of the coin?
0 tails during the first three, which is P(X = 0) when n = 3.
Tails in the fourth, with probability 0.5. So



0.0625 * 100 = 6.25%
Rounding to the nearest tenth of a percent, the correct answer is:
B. 6.3%
Answer:
please forgive me I just want points for my exam
Good to see you here. Now back to the train.
Kaduna, K Lagos, L
Train leaves at 64 km/h
One hour late second train leaves Lagos at 96 km/h.
At the point they meet, if first train has been travelling for "x" hours. Second train has been travelling for (x-1) hour.
At the point the meet, the total distance travelled is equal to 624 km.
Therefore:
64(x) + 96(x-1) = 624
64x + 96x - 96 = 624
160x = 624+96
160x = 720 , x = 720/160 = 4.5
So when they meet, the first train which left Kaduna has travelled= 64x = 64*4.5= 288km from Kaduna.
So it is (624-288) km from Lagos. = 336 Km from Lagos.
Second train which left Lagos has travelled = 96(x-1) = 96(4.5-1) = 336km.
The second train is also 336 km away from Lagos.
Cheers.
It's unreasonable to hope or expect that someone will do a whole sheet of problems for you.
I've arbitrarily chosen to help you with #25:
4x - 9 + 3x + 6 - 9x - 4
Group the x-terms together. Then group the constants together:
4x + 3x - 9x - 9 + 6 - 4
-2x - 7 (answer)