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svp [43]
3 years ago
14

Allen has four times as many cards as Bob, and Jane has twice as many cards as Allen. Together, Allen and Jane have 468 cards. H

ow many cards do Allen, Jane, and Bob EACH have?
Mathematics
2 answers:
Gala2k [10]3 years ago
7 0

Answer:

1008

Step-by-step explanation:

Allen=A

Bob=B

Jane=J

So what we know is 

A=4B

J=2A

A+J=432

What we want to know is

A+J+B=?

So we need to solve for B

The easiest way would be to substitute into the A+J equation so

A+(2A)=432

3A=432

A=144

And we know that 4A=B so 4(144)=B thus B= 576

So 432+576=1008!

blsea [12.9K]3 years ago
4 0

Answer:

Allen: 156 cards, Bob: 39 cards, Jane: 312 cards

Step-by-step explanation:

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Answer:

See figure attached and explanation below.

Step-by-step explanation:

For this case we have the following dataset given:

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And for this case we can use the followinf R code to create the frequency histogram.

> x<-c(0.74, 0.32, 1.66, 3.59, 4.55, 6.47, 9.99,0.7, 0.37, 0.76, 1.9, 1.77, 2.42, 1.09, 2.03, 2.69,2.41, 0.54, 8.32, 5.70, 0.75, 1.96, 3.36, 4.06,12.48)

> length(x)

[1] 25

> hist(x, prob=TRUE)

And for this case we have the histogram on the figure attached. For the number of classes we use the formula of sturges:

k = 1 +3.322 log (n)= 1+3.3 log(25)= 5.61

And for this case we have approximately 6 classes. And that's what we can see on the figure attached

As we can see most of the values are on the left so then we have a right skewed to the right and the distribution is assymetrical, with most of the values between 0 and 6

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Answer:

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Step-by-step explanation:

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