The cost for one bag of pretzels is $1.8, <span>the cost for a box of granola bars is $3.15.
4. The wood bats: x-$24 The metal bats: y</span>-$30 <span>Savelots sold 23 baseball bats: x+y=23 </span><span>The receipts for those bats totaled $606: $24x+$30y=$606 x+y=23⇒x=23-y 24x+30y=606
x=23-y 24*(23-y)+30y=606⇒552-24y+30y=606
x=23-y 6y=54⇒y=9 x=14 14 wood bats and 9 metal bats were sold.
Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars We have Lesley's purchase: 4x+2y=13.50 And Landon's: 1x+5y=17.55 We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55 We add this four times to Lesley's purchase to eliminate the x variable. 2y-20y=13.50-70.2 -18y=-56.7 y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels. x+5*3.15=17.55 x+15.75=17.55 x = $1.80 = price of bag of pretzels
Problem 4. Let w = number of wood bats sold Let m = number of metal bats sold
From sales information we have: w + m = 23 24w+30m=606 Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second. 24*(23-m)+30m=606 552-24m+30m=606 6m=54 m=9 = number of metal bats sold Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
