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Luba_88 [7]
4 years ago
13

Please answer what is true about the function

Mathematics
1 answer:
sineoko [7]4 years ago
6 0
The answer is the last one.  This is because negatives don't work in a square root.
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Arrange these numbers from least to greatest: 5/6, 7/9, -4/5
abruzzese [7]

-4/5, then 7/9 and last is 5/6.
5 0
4 years ago
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Part A.
natali 33 [55]

Answer:

Part A

Martha is incorrect because she will pay 1/4 of the cost.

40%+0.35

0.40+0.35

0.75

0.25=25/100=1/4

Part B

Renee-$340

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Martha-$212.50

6 0
3 years ago
The current cost of a typical desktop computer is $745. The cost in year 1983 was $1,445 with fewer capabilities. What is the CP
labwork [276]
A consumer price index (CPI) measures changes in the price level of market basket of consumer goods and services purchased by households.The annual percentage change in a CPI is used as a measure of inflation
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3 years ago
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PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
Can someone please help me .
dusya [7]

Answer:

for 10. a

for 11. f.

Step-by-step explanation:

5 0
3 years ago
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