The equation of a circle is (x-1)^2 +(y-2)^2=4. What is the center of the circle and what is the radius of the circle?

Mathematics

1 answer:

Virty [35]2 years ago

8 0

Answer:

Step-by-step explanation:

(x-1)²+(y-2)² =4 compare the given equation with the general one

(x-h)² +(y-k)² =r², where (h, k) are coordinates of the center and r is radius

so center is at ( 1, 2) and radius is 2

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The table shows the outputs, y, for different inputs, x: Input (x) 6 12 15 25 Output (y) 14 15 15 16 Part A: Do the data in this

cluponka [151]

Answer:

Part A: No it is not a function

Part B: The equation

Part C: x = 3

Step-by-step explanation:

Part A - The table:

Input (x) Output (y)

6 14

12 15

15 15

25 16

This is a function because it has no repeating inputs values which have alternate outputs. Each input is assigned exactly one output.

Part B - The relation y = 7x - 15 has the value y = 27 when x = 6. You can find it by substituting into the equation.

y = 7(6) -15

y = 42 - 15

y = 27

The value of the relation in the table when x = 6 is y = 14. The equation has the greater value.

Part C: To find when y = 6, set it equal to 6 and solve for x.

6 = 7x - 15

21 = 7x

3 = x

5 0

2 years ago

Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.

guapka [62]

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