Find the midpoint:
m= x1+x2/2; y1+y2/2
m= 9+-1/2; 8+-2/2
m= 8/2; 6/2
m= (4,3)
(4,3) is your answer.
I hope this helps!
~kaikers
Answer:
Step-by-step explanation:
1. Move the 6 to the other side: x^2 +4x =6
2. Square half the coefficient of the x term: (4/2)^2 = 4
3. Add this 4, and then subtract this 4, from x^2 + 4x:
x^2 +4x + 4 - 4 =6
4. Rewrite this perfect square as the square of a binomial:
(x + 2)^2 - 4 = 6
5. Add 4 to both sides: (x + 2)^2 = 10
6. Find the sqrt of both sides: x + 2 = √
Answer:
-x^4y^2 +7x^3y^3 +2x^2y^4 -3xy^5
Step-by-step explanation:
The powers of x in the terms of the given expression are ...
4, 3, 1, 2
so, we want to swap the last two terms to put them in the desired order:
-x^4y^2 +7x^3y^3 +2x^2y^4 -3xy^5
It looks correct to me :)