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mixas84 [53]
3 years ago
14

P − 10p + -5p + 14p − -9p − 2 = -20

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

You will need to work left to right.

p - 10p + -5p +14p - -9p - 2 = -20

-9p + -5p +14p - -9p - 2 = -20

-14p +14p - -9p - 2 = -20

0p- -9p - 2 = -20

9p - 2 = -20

Then you will want to eliminate 2 by adding it to both sides

9p = -18

Then divide by 9 to isolate P

p=-2


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Find the smallest number which when divided by 12,15,18&27 leaves as remainder 8,11,14,23 respectively.
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Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{536}}}}}

Step-by-step explanation:

Solution :

Here, 12 - 8 = 4

15 - 11 = 4

18 - 14 = 4

27 - 23 = 4

Thus, every divisor is greater than its remainder by 4. So, the required smallest number is the difference of the L.C.M of the given number and 4

<u>Finding </u><u>the</u><u> </u><u>L.C</u><u>.</u><u>M</u>

First of find the prime factors of each numbers

12 = 2 × 2 × 3

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18 = 3 × 3 × 3

27 = 3 × 3 × 3

Take out the common prime factors : 3 , 3 and 3

Also take out the other remaining prime factors : 2 , 2 and 5

Now, Multiply those all prime factors and obtain L.C.M

L.C.M = Common factors × Remaining factors

= 3 × 3 × 3 × 2 × 2 × 5

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L.C.M of 12 , 15 , 18 and 27 = 540

So, The required smallest number = 540 - 4

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Hope I helped!

Best regards!!

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4 years ago
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The fraction 2/3 has the greatest value.

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A student wants to determine whether or not a value in her data is an outlor. She has calculated Q, 4, median 5, and Q, - 10. Wh
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Answer:

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Step-by-step explanation:

Although the typing has some typographical issues. We could extract the following:

First quartile (Q1 => 0.25) = 4

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       ==>[Q3 + Q1] = 10+4 = 14.

NB: If all our assumed values from the question are correct!

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