J=-8c²-4cd-d²
k=-3c²+7cd-3d²
j+k=
-8c²-4cd-d²-3c²+7cd-3d²
-11c²-4d²+3cd
The lowest common multiple is 216 (D)
Answer:

Step-by-step explanation:
Solution :
Here, 12 - 8 = 4
15 - 11 = 4
18 - 14 = 4
27 - 23 = 4
Thus, every divisor is greater than its remainder by 4. So, the required smallest number is the difference of the L.C.M of the given number and 4
<u>Finding </u><u>the</u><u> </u><u>L.C</u><u>.</u><u>M</u>
First of find the prime factors of each numbers
12 = 2 × 2 × 3
15 = 3 × 5
18 = 3 × 3 × 3
27 = 3 × 3 × 3
Take out the common prime factors : 3 , 3 and 3
Also take out the other remaining prime factors : 2 , 2 and 5
Now, Multiply those all prime factors and obtain L.C.M
L.C.M = Common factors × Remaining factors
= 3 × 3 × 3 × 2 × 2 × 5
= 540
L.C.M of 12 , 15 , 18 and 27 = 540
So, The required smallest number = 540 - 4
= 536
Hope I helped!
Best regards!!
Answer:
2/3
Step-by-step explanation:




The fraction 2/3 has the greatest value.
Answer:
14
Step-by-step explanation:
Although the typing has some typographical issues. We could extract the following:
First quartile (Q1 => 0.25) = 4
Second quartile/median (Q2 => 0.50) = 5
Third quartile (Q3 => 0.75) = 10.
The upper fence (maximum):
==>[Q3 + Q1] = 10+4 = 14.
NB: If all our assumed values from the question are correct!