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liberstina [14]
4 years ago
8

J= -8c^2 - 4cd - d^2 k= -3c^2 +7cd - 3d^2 j+k =

Mathematics
1 answer:
irina [24]4 years ago
6 0
J=-8c²-4cd-d²
k=-3c²+7cd-3d²
j+k=
-8c²-4cd-d²-3c²+7cd-3d²
-11c²-4d²+3cd
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It’s easy please help please please
lions [1.4K]

Step-by-step explanation:

4x - 2y = 8

y = -2

4x -2(-2) = 8

4x + 4 = 8

4x = 4

x = 1

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3 years ago
Someone please please help<br> me i only have a few minutes left !!!
Juli2301 [7.4K]

Answer:

5 8/15 I rly hope this helps man

8 0
3 years ago
Is 645 round to 600 when rounded to the nearest ten
Juliette [100K]
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6 0
4 years ago
Prove the divisibility of the following numbers:
ratelena [41]

Make use of prime factorizations:

16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}

Both terms have a common factor of 2^{15}:

16^5+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33

- - -

The second one is not true! We can write

15^7+5^{13}=(3\cdot5)^7+5^{13}=3^7\cdot5^7+5^{13}

Both terms have a common factor of 5^7:

15^7+5^{13}=5^7\left(3^7+5^6\right)

Since 30=5\cdot6, and 5\mid5^7, we'd still have to show that 5^6(3^7+5^6) is a multiple of 6. This is impossible, because 6=3\cdot2 and there is no multiple of 2 that can be factored out.

4 0
3 years ago
Read 2 more answers
Solve the following system of equations.
vodomira [7]

Answer:

a = 6/5

b = 7/8

c = 1/5

Step-by-step explanation:

We want to make two of these equations be in terms of the same variable, so let's solve the first and third  in terms of b.  

5a-24b=-15 -> -3 + 24b/5 = a

48b+35c = 49 -> 49/35 - 48b/35 = 7/5 - 48b/35 = c

Now we can replace the a and c in the second equation and solve for b.

10a+45c=21

10(-3+24b/5)+45(7/5 - 48b/35) = 21

-30 + 48b + 63 - 432b/7 = 21 -> -12 = -96b/7 -> b=7/8

Now we can plug b back into the other two to solve for a and c.  I will leave that to you unless you would like the steps there.

7 0
3 years ago
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