Answer:
10th term is 10
Step-by-step explanation:
The nth term for finding the geometric progression is expressed as;
Tn = ar^n-1
a is the first term
r is the common ratio
n is the number of terms
a11 = ar^11-1
a11 = ar^10
Since a11 = -5 and r = -1/2
-5 = a(-1/2)^10
-5 = a(1/1024)
a= 1024 * -5
a = -5120
Nest is to get the 10th terms
a10 = ar^9
a10 = -5120 * (-1/2)^9
a10 = -5120 * -1/512
a10 = 10
Hence the 10th term of the sequence is 10
Answer:
centre = (- 1, - 3 ) , radius = 6
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
given
x² + y² + 2x + 6y = 26 ( collect x and y terms )
x² + 2x + y² + 6y = 26
using the method of completing the square
add ( half the coefficient of the x/ y terms )² to both sides
x² + 2(1)x + 1 + y² + 2(3)y + 9 = 26 + 1 + 9
(x + 1)² + (y + 3)² = 36 ← in standard form
with centre = (- 1, - 3 ) and r = 
= 6
Hello,
A good method for solving this question is creating an equation to solve for the width of the door.
Let w = the width of the door
Let h = the height of the door
The height (h) is twice the width (2w) and one foot more (+1).
We can make the equation h = 2w + 1
Now, we are given that the height of the door is 7 feet, so h = 7.
We can simply plug in 7 for h in the equation to solve for w.
So, we have h = 2w + 1
7 = 2w + 1
Subtract by 1 on both sides to get:
6 = 2w
Divide by 2 on both sides to get:
w = 3
The width of the door is 3 feet.
However, we should check out answer with the given question to make sure it checks out.
We are given that the height of the door is one foot more than twice its width, and the height of the door is 7 feet.
Twice the width is 6 feet, and one foot more than that is 7 feet. Our answer checks out.
The width of the door is 3 feet.
Hope this helps!
Answer:
I tried solving it and didn't get same exact numbers but I got 8.67 million people so it might be answer choice B.
BN. This is another correct name for the segment.
