Simplify the radical by breaking the radicand up into a product of known factors.
Your answer is A. -0.5
Answer:
What grade work is it? I don't really know what it says. Sorry, please can you type it out?
Step-by-step explanation:
Answer:
We cannot infer at the 10% significance level that the assumption of ski centers is wrong
Step-by-step explanation:
The null hypothesis for this question can be stated as
Null hypothesis H0: =4
Alternate hypothesis Ha:
The test is two tailed
Standard Deviation –
= 2
z=(4.84-4)/(2/sqrt(63))
=3.33
Z(0.1/2)=1.645 is less than Z =3.334
Hence, we will reject H0
Hence, the average growth skier ski’s four times a year is not true
To find the answer you first have to turn 4 1/2 a mixed number into an improper fraction. To do this you must multiply the denominator with the whole number to get 8 after add 1 to get 9. to finish off the improper fraction put the 9 as the numerator and keep the denominator of 2. After this you will have 9/2 ÷ 3/4. Remember Keep Change Flip. this means keep 9/2 change the sign from division to multiplication and flip 3/4 to 4/3. After this you will have 9/2 x 3/4. Now multiply the numerators and multiply the denominators. 9x4 is 36 and 2x3 is 6 you now have 36/6. Lucky for you 36 goes into 6, 6 times. So the answer is 6. If you have anymore questions please dont hesitate to ask :) Hope this helps. If you are having trouble look at this link on youtube about dividing fractions. https://www.youtube.com/watch?v=uMz4Hause-o
The reason for this has to do with finding the area of a square. When you are looking for the area of a square, you use the rectangle formula (since a square is also a rectangle).
The formula is Area = Length * Width
However, since in a square, the length and width are the same, both get changed to the word "Side". As a result, we get the following formula.
Area = Side * Side
This can be simplified to:
Area = Side^2.
Since each number to the second power also shows the area of a square with that given length sides, it can also be called "squared".
