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DanielleElmas [232]
3 years ago
15

Find the product. 0.75(68)

Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

51

Step-by-step explanation:

i used a calculator. The answer is 100% sure to be correct.

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(15a -7b+4c) -(-3a-6b+12c) adalah​
Firlakuza [10]

Answer:

15a-7b+4c+3a+6b-12c

=18a-b-8c

8 0
3 years ago
the left and right page numbers of an open book are two consecutive integers whose sum is 593. find these page numbers ​
kobusy [5.1K]

Answer:

296 and 297

Step-by-step explanation:

a+a+1=593

2a+1=593

2a=592

a=296

6 0
3 years ago
which functions have a range of all real numbers ? check all that apply. A. y=csc x B. y=sec x C. y=tan x D. y= cot x
Natalka [10]

None of these. All of these functions are defined as ratio of trigonometric functions.

Trigonometric functions have infinite zeroes, so when you put them in the denominator, they lead to infinitely many points of ill-definition.

Specifically, we have:

\csc(x) = \dfrac{1}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

\sec(x) = \dfrac{1}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\tan(x) = \dfrac{\sin(x)}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\cot(x) = \dfrac{\cos(x)}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

4 0
3 years ago
Pls help i am on a timer
stich3 [128]

Answer:

x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

x^2 +  (-1)^2 = 1 + (-1)^2

(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\

⇒ take the square root of both sides;

x-1 = +/- \ \ \sqrt{2} \\\\x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Therefore, option B is the right solution.

3 0
2 years ago
PLS HELP THIS IS DUE AT 11:59pm
Fudgin [204]

Answer:

I think system 4 has no solution

Step-by-step explanation:

I'm sorry if you get it wrong

6 0
3 years ago
Read 2 more answers
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