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3 years ago

6

There are 12 pencils and eight pens in a cup holder select all of the simplified ratios that could be written (MULTIPLE CHOICE)

A: 6 to 4 B: 5 to 3 C:4:10 D: 5:2 E: 3/2 F:5/2 I WILL GIVE BRAINLIEST TO FIRST ANSWER

1 answer:

Tasya [4]3 years ago

4 0

A and E are the correct answers:

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Can someone help me please

natali 33 [55]

Answer:

The answer to number one is 11√17

The answer to number two is 4

Step-by-step explanation:

In number one: once you get both radicands to be equal, then you can add them. Like of it like 3x+2x. The x’s are like terms, so you can add them together.

In number two: the √5 on the top and bottom cancel out. This leaves 12/3 which is equal to 4.

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3 years ago

Someone help me please

Darina [25.2K]

It’s the second one

8 0

3 years ago

What is the volume of the cube?

weeeeeb [17]

Hi !
The volume of the cube is :
18 × 18 × 18= 5 832 mm³
The answer is D.

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4 years ago

Find the midpoint of the line segment with the endpoints A and B.<br> A(10,6); B(8,4)

MatroZZZ [7]

Answer:

(9,5)

Step-by-step explanation:

10+8/2=18/2=9

6+4/2=10/2=5

4 0

3 years ago

The maximum afternoon temperature in Granderson is modeled by t=60-30 cos (x<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="T

kicyunya [14]

The equation is $t=60-30 cos (x \frac{\pi}{6})$

the -30 expression, is subtracting, if negative, from the 60
if the cosine returned is negative, you'd end up with a +30,
negative * negative = positive

and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
positive and and it's highest

when does that happen, when cosine is negative and at its highest,
well, cosine range is $-1\le cos(\theta ) \le 1$
so the lowest value cosine can provide is -1, when is cosine -1?
well, at $\pi$

so... let's find a value that makes that expression to $cos(\pi)$

$\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6
\\\\
thus
\\\\
t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )
\\\\
t=60-30[-1]\implies t=60+30\implies t=90$

----------------------------------------------------------------------------------------
so...for August, that'll mean

$\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7
\\\\
t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)
\\\\
t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o$

4 0

3 years ago