answer: you would just substitute all of the values you see for b into the equation where there's a b
Answer:
2
Step-by-step explanation:
example A(2a,0),B(2b,0)
C(2b,2c),D(2a,2c)
mid point of AC=((2a+2b)/2,(0+2c)/2)=(a+b,c)
mid point of BD=((2b+2a)/2,(0+2c)/2)=(a+b,c)
∴midpoint of diagonals same or diagonals bisect each other.
Answer: 20p³+30p²-13p-12
Step-by-step explanation:
2(-4p-6)-5p²(-4p-6)-5p
-8p-12+20p³+30p²-5p
20p³+30p²-13p-12
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