Solve for f(-1) f(x)=-3x +3 f(-1)=?

Mathematics

1 answer:

krok68 [10]2 years ago

6 0

9 or -9 ...if I’m wrong sorry

You might be interested in

Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.

natulia [17]

$\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k$

Divergence is easier to compute:

$\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}$

$\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}$

Curl is a bit more tedious. Denote by $D_t$ the differential operator, namely the derivative with respect to the variable $t$ . Then

$\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}$

$\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k$

$\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k$

5 0

3 years ago

An airline offers daily flights between Chicago and Denver. The total monthly cost C (in millions of dollars) of these flights c

Ira Lisetskai [31]

Answer:

6250

Step-by-step explanation:

Fill in the given number and solve for x. The answer is 1000x, rounded.

$C=\sqrt{0.2x+1}\\\\1.5=\sqrt{0.2x+1} \quad\text{use given value for C}\\\\2.25=0.2x+1 \quad\text{square both sides}\\\\1.25=0.2x \quad\text{subtract 1}\\\\6.25=x \quad\text{multiply by 5}$