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Dmitrij [34]
3 years ago
15

A library checked out 52 books. 24 are fiction books what is the ratio for fiction to non fiction books. Please show how it is d

one. Thanks
Mathematics
2 answers:
Neko [114]3 years ago
8 0
28 were non fiction, hope i helped because i did not get the question to well
 
agasfer [191]3 years ago
5 0
Since there are 24 fiction books and 52 books in total, you can start with subtracting them both to find the amount of non-fiction books. 52-24=28, so 28 non-fiction books are currently checked out. Now for the fun part. There are two ways I know how to do this, so let's start. One way is that you can put a ':' between the two numbers. For example, since we are trying to find fiction books to non-fiction, we would say 24:28. The first number will represent the first thing they ask for (fiction), and the second number will represent the second thing they ask for (non-fiction). Another way to do this is by putting the numbers as a fraction. For example, you could put 24/28. It will still mean the same thing, and it will not change the outcome. I hope this helps! :)
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Find the slope of the line through the given points. (3, 7) and (3, −8)
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Okay, so we will be using the formula y1-y2/x1-x2:

7--8/3-3=15/0

Now, we can't divide by zero so we can just say the slope of the line is 0

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3 years ago
The height of a hill, h(x), in a painting can be written as a
matrenka [14]

Answer:

First option: 6\ inches

Step-by-step explanation:

<h3> The complete exercise is: "The height of a hill, h(x), in a painting can be written as a function of x, the distance from the left side of the painting. Both h(x) and x are measured in inches h(x) = -\frac{1}{5}(x)(x -13). What is the height of the hill in the painting 3 inches from the left side of the picture?</h3>

You have the following function provided in the exercise:

h(x) = -\frac{1}{5}(x)(x -13)

You know that h(x) represents the height of the hill (in inches) and "x" represents the distance from the left side of the painting (in inches)

Knowing that you can determine that, if the painting 3 inches from the left side of the picture, the value of "x" is the following:

x=3

Therefore, you need to find the value of   h(x) when  x=3 in order to solve this exercise.  

So, the next step is to substitute  x=3 into the function:

h(x) = -\frac{1}{5}(3)(3 -13)

And finally, you must evaluate in order to find h(3).

You get that this is:

h(3) = -\frac{1}{5}(3)(-10)\\\\h(3) = -\frac{1}{5}(-30)\\\\h(3)=6

4 0
3 years ago
Read 2 more answers
Write an algebraic expression for the word phrase c divided by 7.
Y_Kistochka [10]

Answer:

D. c/7

Step-by-step explanation:

An algebraic expression refers to the equation. In the question, it says to divide a number (c) by seven, giving you c/7

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3 years ago
Write a problem that can be solved with a bar model that shows equal groups of liters
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8 0
3 years ago
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on
boyakko [2]

<u>Answer:</u>

<em>Mathew invested</em><em> $600 and $2400</em><em> in each account.</em>

<u>Solution:</u>

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest (I_1) earned in first account for one year,

\text {simple interest}=\frac{\text {pnr}}{100}

Where  

p = amount invested in first account

n = number of years  

r = rate of interest

hence, by using above equation we get (I_1) as,  

I_{1}=\frac{P \times 1 \times 3}{100} ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest (I_2) earned in second account,

I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

I = I_1+ I_2 ---- eqn 4

By substituting eqn 1 , 2, 3 in eqn 4

\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}

\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400  

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600  

Hence, Mathew invested $600 and $2400 in each account.

3 0
3 years ago
Read 2 more answers
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