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s344n2d4d5 [400]
3 years ago
15

Determine if the following set is a vector space with the indicated operations. The set. V of all 2 x 2 real matrices A with sta

ndard matrix addition in M22 but scalar multiplication defined by a * A :=aA", a ER.
Mathematics
1 answer:
lakkis [162]3 years ago
7 0

Answer: so the addition is not a problem here, i understand that you write a*A = a.A so is a scalar product. if your matrix is A1, A2, A3, A4, and you multiply this with an scalar a defined in the real set.

then a*A = a.A1, a.A2, a.A3, a.A4

so this multiplication still gives you a 2x2 matrix, that is in your space.

so the defined here is a Vector space, because the addition of two of his objects results in other object in the set.

And also has a scalar multiplication that if you feed it with an object on the set, it returns another object on the set.

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Slove algebraically<br><br>3x - 4y = -24<br>x +4y=8<br>​
Vanyuwa [196]

Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3

<u>Solution:</u>

We have been given two equations which are as follows:

3x - 4y = -24   ----- eqn 1

x + 4y = 8   -------- eqn 2              

We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.

We rearrange eqn 2 as follows:

x + 4y = 8

x = 8 - 4y  ------eqn 3

Now we substitute eqn 3 in eqn 1 as follows:

3(8 - 4y) -4y = -24

24 - 12y - 4y = -24

-16y = -48

y = 3

Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:

x = 8 - 4(3)

x = 8 - 12  = -4

Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.

5 0
3 years ago
7(6m - 4) = -364 pls try and show work thanks!
quester [9]

Answer:

7(6m - 4) = -364

multiply 7 for both variables in the parenthesis

42m - 28 = -364

move 28 to other side

42m= -336

divide 42 on both sides

m= -8

3 0
3 years ago
Read 2 more answers
A football team loses 3 yards, gains 12 yards, gains 10 yards, and then loses 15 yards. Did the team gain yards or lose yards ov
e-lub [12.9K]

Answer: the answer is 4

Step-by-step explanation:

5 0
3 years ago
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
Which equation can be used to solve for the value<br> of x?
Over [174]

Answer:

the orange one

Step-by-step explanation:

the bottom angles are gonna be the same and a triangle is 180 degrees total so

3 0
3 years ago
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