Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula
The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.
![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 
=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Answer: $1114.91
Step-by-step explanation:
The formula for compound interest is
Where
A = final amount
P = initial principal balance (1030 for this)
r = interest rate (0.04 for this)
n = number of times interest applied per time period (2 for this)
t = number of time periods elapsed (2 for this)
This rounds up to $1114.91
The answer is C because it’s the same line
Answer:
√446 ≈ 21.12 cm
Step-by-step explanation:
The longest dimension of a rectangular prism is the length of the space diagonal from one corner to the opposite corner through the center of the prism. The Pythagorean theorm tells you the square of its length is the sum of the squares of the dimensions of the prism:
d² = (15 cm)² +(11 cm)² +(10 cm)² = (225 +121 +100) cm² = 446 cm²
d = √446 cm ≈ 21.12 cm
The longest line segment that can be drawn in a right rectangular prism is about 21.12 cm.
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<em>Additional comment</em>
The square of the face diagonal is the sum of the squares of the dimensions of that face. The square of the space diagonal will be the sum of that square and the square of the remaining prism dimenaion, hence the sum of squares of all three prism dimensions.
Answer:
Lol ..... I don't know the answer :D :P
Step-by-step explanation:
L.H.S x 0 = 0
R.H.S x 0 = 0
L.H.S = R.H.S
Hence , proved .....
