Answer:
The population will reach 34,200 in February of 2146.
Step-by-step explanation:
Population in t years after 2012 is given by:

In what month and year will the population reach 34,200?
We have to find t for which P(t) = 34200. So



Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:

So 
Then



We only take the positive value.
134 years after 2012.
.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.
So the population will reach 34,200 in February of 2146.
Answer:
17
Step-by-step explanation:
54 has 4 ones
and 5 tens
37 has 7 ones
and 3 tens
subtracting ones
7 ones are taken from 54
so along with the existing 4, 1 ten is decreased and another 3 ones are decreased resulting in 7 ones now
now 54 has 5-1= 4 tens
subtracting tens we get 4-3=1
Therefore 1 ten and 7 ones
⇒ 17
I will solve your system by substitution.<span><span>x=<span>−2</span></span>;<span>y=<span><span><span>23</span>x</span>+3</span></span></span>Step: Solve<span>x=<span>−2</span></span>for x:Step: Substitute<span>−2</span>forxin<span><span>y=<span><span><span>23</span>x</span>+3</span></span>:</span><span>y=<span><span><span>23</span>x</span>+3</span></span><span>y=<span><span><span>23</span><span>(<span>−2</span>)</span></span>+3</span></span><span>y=<span>53</span></span>(Simplify both sides of the equation)
Answer:<span><span>x=<span>−<span><span>2<span> and </span></span>y</span></span></span>=<span>5/3
<span>
so the answer is B (the second choice)
(Hope it helped ^_^)
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First you substitute in the values so you have
V^2=(64)20
then you just simplify it
V^2=1280
V=the square root of 1280
V= about 35.7770876
or
V=the square root of 256 times <span>the square root of 5
V=16 times </span><span>the square root of 5
also V would typically be called velocity. it's very similar to speed but it is just easier to remember because it starts with a V</span>