The protractor of the radius squared is 2x the volume shown
<h3>
Answer: 6a^3-6a^2b+3ab-3b^2</h3>
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Work Shown:
(2a^2+b)(3a-3b)
c(3a-3b) ..... let c = 2a^2+b
3ac-3bc .... distribute
3a(c)-3b(c)
3a(2a^2+b)-3b(2a^2+b) .... plug in c = 2a^2+b
3a(2a^2)+3a(b)-3b(2a^2)-3b(b) ... distribute
6a^3+3ab-6a^2b-3b^2
6a^3-6a^2b+3ab-3b^2
You could also use the FOIL rule to get the same result. The box method is a visual way to keep track of the terms.
Answer:
Step-by-step explanation:
The exterior angle in a triangle is equal to the sum of the interior opposite angles in a triangle
Therefore,
Now solve for x
Now let's solve for the exterior angle
Hope this helps you.
Let me know if you have any other questions :-)
It will have to be D 23 ft
Recall that the equation to solve for the volume of a cone is 1/3 * area of base * h
Since we have the radius and the height of the cone, we can put these into an equation:
1/3 * π(1.5)^2 * 4.5
(π(1.5)^2 is because we need to use the equation of the area of a circle in order to find the area of the base)
Square the 1.5:
1/3 * 2.25π * 4.5
The value of π is 3.14, so input that value:
1/3 * 2.25(3.14) * 4.5
Multiply 2.25 and 3.14:
1/3 * 7.065 * 4.5
Multiply all the values (You should use a calculator for this last part, since doing this by hand is a bit impractical):
1/3 * 7.065 * 4.5 = 10.5975
The sugar cone must be filled with 10.5975 cubic inches of ice cream.
-T.B.
