3 years ago

If sinX= 0.9, what is the value of cos X? Round the value to the nearest thousandth.

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

6 0

Answer: sqrt(19)/10

Step-by-step explanation:

sinx=0.9

x=arcsin(0.9)

Insert x for cos(x):

cos(arcsin(0.9)=

Use identify $cos(arcsin(x))=\sqrt{1-x^{2} }$ , so

$\sqrt{1-(\frac{9}{10})^{2}} =\sqrt{\frac{19}{100} } =\frac{\sqrt{19}}{10}$

Sorry if this is confusing.

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