Answer:
Lee has 19 nickels and 8 dimes
Step-by-step explanation:
hello, I think I can help you with this
Step 1
Let
value of a nickel=$0.05
value of a dime=$0.10
number of nickels=N
number of nickels=D
According to the question data Lee has $1.75 in dimes and nickels.
0.05N+0.1D=1.75,equation(1)
also, the number of nickels is 11 more than the number of dimes.mathematical speaking
N=11+D,equation(2)
Step 2
replace N from equation (2) into equation (1)
0.05N+0.1D=1.75
0.05(11+D)+0.1D=1.75
Now, solve for D
0.55+0.05D+0.1D=1.75
0.15D=1.75-0.55
D=1.2/0.15
D=8
Step 3
replace the value of D into equation(2) to obtain N
N=11+8
N=11+8
N=19
Hence, Lee has 19 nickels and 8 dimes
Have a great day.
<span>You can probably just work it out.
You need non-negative integer solutions to p+5n+10d+25q = 82.
If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80.
So this is the same as n + 2d + 5q ≤ 16
So now you simply have to "crank out" the cases.
Case q=0 [ n + 2d ≤ 16 ]
Case (q=0,d=0) → n = 0 through 16 [17 possibilities]
Case (q=0,d=1) → n = 0 through 14 [15 possibilities]
...
Case (q=0,d=7) → n = 0 through 2 [3 possibilities]
Case (q=0,d=8) → n = 0 [1 possibility]
Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81
Case q=1 [ n + 2d ≤ 11 ]
Case (q=1,d=0) → n = 0 through 11 [12]
Case (q=1,d=1) → n = 0 through 9 [10]
...
Case (q=1,d=5) → n = 0 through 1 [2]
Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42
Case q=2 [ n + 2 ≤ 6 ]
Case (q=2,d=0) → n = 0 through 6 [7]
Case (q=2,d=1) → n = 0 through 4 [5]
Case (q=2,d=2) → n = 0 through 2 [3]
Case (q=2,d=3) → n = 0 [1]
Total from case q=2: 1 + 3 + 5 + 7 = 16
Case q=3 [ n + 2d ≤ 1 ]
Here d must be 0, so there is only the case:
Case (q=3,d=0) → n = 0 through 1 [2]
So the case q=3 only has 2.
Grand total: 2 + 16 + 42 + 81 = 141 </span>
In math, Exponentiation refers to the operation of raising one quantity to the power of another. See the program running the exponentiation below.
<h3>What is the required code?</h3>
The code is given below:
number_of_days = 30
amount_after_30days = 0.01 * (2 ** number_of_days)
# print the amount
print(amount_after_30days)
Learn more about exponentiation at;
brainly.com/question/11975096
#SPJ1
I think it’s B (0, 0) (5, -3), (4, 1).
