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2 years ago

Please help me graph and find the slope. I need an answer ASAP will mark brainliest!

Mathematics

1 answer:

Xelga [282]2 years ago

6 0

Answer:

y = 0.6x

Step-by-step explanation:

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Slope-Intercept Form: y = mx + b

Step 1: Find slope <em>m</em>

m = (1.2 - 0)/(2 - 0)

m = 1.2/2

m = 0.6

y = 0.6x

Step 2: Find y-intercept <em>b</em>

(0, 0) is y-int

Equation is y = 0.6x

Step 3: Graph

Use point (-5, -3) and (0, 0) to graph

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3 years ago

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lys-0071 [83]

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Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

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3 years ago