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insens350 [35]
3 years ago
7

D'Naisa mixed her favorite shade of orange paint. She had 111 gallon of orange paint and added 222 quarts of yellow paint and 33

3 pints of red paint. How many quarts of paint did D'Naisa mix?
Mathematics
2 answers:
zheka24 [161]3 years ago
4 0

Answer:

7.5 Quarts

Step-by-step explanation:

natka813 [3]3 years ago
3 0

Answer:

7.5 Quarts

Step-by-step explanation:

D'Naisa mixed the following:

  • 1 gallon of orange paint
  • 2 quarts of yellow paint
  • 3 pints of red paint.

We are to determine in total, the number of quarts of paint that she mixed. this is done by converting each of the volume to quart.

<u>1 gallon of orange paint</u>

  • 1 gallon = 4 Quarts
  • Orange Paint=4 Quarts

<u>3 pints of red paint.</u>

  • 1 pint =0.5 quart
  • 3 Pints =3 X 0.5 Quart
  • =1.5 Quart of red paint

Therefore,

Total Volume of Paint Mixed in quart= Volume of Orange+Yellow+Red

=4+2+1.5

=7.5 Quarts

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The simulation of the medicine and the bowler hat are illustrations of probability

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  • The probability that the medicine is effective on none is 0
  • The probability that the bowler hits a headpin 4 out of 5 times is 0.3281

<h3>The probability that the medicine is effective on at least two</h3>

From the question,

  • Numbers 1 to 7 represents the medicine being effective
  • 0, 8 and 9 represents the medicine not being effective

From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two

So, the probability is:

p = 23/30

p = 0.767

Hence, the probability that the medicine is effective on at least two is 0.767

<h3>The probability that the medicine is effective on none</h3>

From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none

So, the probability is:

p = 0/30

p = 0

Hence, the probability that the medicine is effective on none is 0

<h3>The probability a bowler hits a headpin</h3>

The probability of hitting a headpin is:

p = 90%

The probability a bowler hits a headpin 4 out of 5 times is:

P(x) = nCx * p^x * (1 - p)^(n - x)

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P(4) = 5C4 * (90%)^4 * (1 - 90%)^1

P(4) = 0.3281

Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281

Read more about probabilities at:

brainly.com/question/25870256

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