Answer:
Juan wins the race
Step-by-step explanation:
<u>The graph is shown in attached image.</u>
<u />
The black line is Juan's graph.
The green line is Antonio's graph.
The graph shows the distance (y-axis) with time (x-axis).
The end of the curve(s) means the end of the race. Both curve's ending point in y-axis is 4 miles so the end of the race is 4 miles.
But in x-axis, we see the time:
Juan finishes at 13 minutes
Antonio finishes at 15 minutes
<u>Definitely Juan wins the race</u>
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20h%3D-16t%5E2%2B%5Cstackrel%7B%5Cstackrel%7Bv_o%7D%7B%5Cdownarrow%20%7D%7D%7B65%7Dt)
now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.
Answer:
1
Step-by-step explanation:
hope this help:) I use slop formula
1/5( 5/2 x 4/7 -11/7) + 3/28
Multiply the terms (5/2 x 4/7) in bracket then subtract it from 11/14. Result will be 10/7.
Then multiply 1/5 with 10/7. The result will be 2/7.
2/7 + 3/28 = 11/28
T
-5x - 5 = 3x + 19
---Move the x's to one side
-5x - 3x - 5 = 3x - 3x + 19
-8x - 5 = 19
---Isolate the -8x by removing the -5 from the left side
-8x - 5 + 5 = 19 + 5
-8x = 24
---Divide both sides by -8 to get x by itself
x = -3
Hope this helps!
