The rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have:
The distance traveled by passenger train = 245 miles
The distance traveled by freight train = 245 miles
The time takes for both trains is the same.
Let's suppose the rate of the passenger train is x and the rate of the freight train is y;
As we know,
Distance = speed×time
245/x = 200/y
200x = 245y
200x - 245y = 0 ..(1)
x = 15 + y ..(2)
Equations (1) and (2) represent the situation.
After solving equations (1) and (2):

Thus, the rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
Learn more about the linear equation here:
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P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529
D= V L^2+l^2= 17
L^2+l^2=289
so 289+2l*L=529
2l*L=529-289=240
l*L=240:2
A=120
The distance from a to c is ten units
Answer:
-4<3, 5>-5, -6<0, -4>-12, -9<1, -8<100, -90<5, -3<-2, -7<-5, 10>3
Step-by-step explanation: