Answer:
Area of the trapezium ABDE = 30 cm²
Step-by-step explanation:
Area of a trapezium = 
Here,
and
are the parallel sides of the trapezium
h = Distance between the parallel sides
From the picture attached,
ΔCAE and ΔCBD are the similar triangles.
So by the property of similarity their sides will be proportional.


CE = 
CE = 12 cm
Therefore, DE = CE - CD
DE = 12 - 8 = 4 cm
Now area of trapezium ABDE = 
= 
= 30 cm²
Therefore, area of the trapezium ABDE = 30 cm²
13 cm+ 13 cm= 26 cm, 26 cm is the answer to Part B.
How to solve ; -3m + 18 - 4 = 14. that equals -3m+14
Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.