3x^0 (2x^3y^2)^4
--------------------------
(4x^7y^4) ^2
= 3 * 1 (2x^3y^2)^4
-------------------------- Zero Exponent Property X^0 =1
(4x^7y^4) ^2
3 (2^4 *x^3*4 y^2*4)
-------------------------- power of a power property x^a ^b = x^(a*b)
4^2 x^7*2 y^4*2
3 *16 *x^12 y^8
-------------------------- simplify
16 x^14 y^8
3 *x^12 y^8
-------------------------- simplify
x^14 y^8
3 *x^(12-14) y^(8-8)
-------------------------- Quotient of Power X^a/ X^b = X^ (a-b)
3x^-2 y^0 simplify
3x^-2 *1 Zero Exponent Property X^0 =1
3 / x^2 Negative exponent property x^-a = 1/x^a
Answer:
A) x^2-10x+25 B)X^3-15x^2+75x-125
Step-by-step explanation:
H^2=(x-5)(x-5)=x^2-10x+25
H^3=(x-5)(x-5)(x-5)=X^3-15x^2+75x-125
Answer:
<em>-5, -3 = Quadrant |||</em>
Step-by-step explanation:
-3, 5 = Quadrant ||
4, 2 = Quadrant |
2, -4 = Quadrant |||| (Quadrant |||| is also known as Quadrant IV)
<u><em>~ LadyBrain</em></u>
Rotation and reflection do not alter the dimensions of the figure.
The appropriate choice is ...
B- It has the same dimensions as the original figure.
Answer:
The answer to your question is There is only one solution (0, -2)
Step-by-step explanation:
Data
Equation 1 x - y = 2
Equation 2 x + y = -2
Solve for y
Equation 1 y = x -2
y = x - 2
Equation 2 y = - x - 2
See the graph below
These lines cross in point (0 ,-2), that is the only solution.
If the lines have not crossed, they were parallel lines.