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castortr0y [4]
3 years ago
7

David’s family is driving from New York to Florida. They know the distance they will travel is about 1100 miles . If a map has a

scale of 1 in = 80 mi about how far will the trip be on the map ?
Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

13.75 inches

Step-by-step explanation:

To find an estimated distance on the map, we can simply create a proportion.

Let X represent the unknown distance in inches on the map.

1100 miles / 80 miles = X inches / 1 inch

Now let's solve for X.

X inches = (1100 miles / 80 miles) * 1 inch

X inches = 13.75 inches

So the approximate travel distance on the map will be 13.75 inches.

elena-s [515]3 years ago
4 0

You can do the proportion  

1 inch/ 80 miles =x inch/ 1100 miles

1100=80x

11oo divided by 80 equals 13.75

The trip would be about 13.75 inches on the map

Feel free to brainliest :)

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A average amount of money on deposit in a savings account is $7500. Suppose a random sample of 49 accounts shows the average in
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Answer:  

z=-3.79

p_v =2*P(z  

Step-by-step explanation:  

1) Data given and notation  

\bar X=6850 represent the mean average amount of money on deposit in savings account for the sample  

\sigma=1200 represent the population standard deviation for the sample  

n=49 sample size  

\mu_o =7500 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean for the amount of money on deposit in savings account differs from 7500, the system of hypothesis would be:  

Null hypothesis:\mu =7500  

Alternative hypothesis:\mu \neq 7500  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{6850-7500}{\frac{1200}{\sqrt{49}}}=-3.79  

4)P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

5) Conclusion  

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