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Elena-2011 [213]
3 years ago
5

Help please Algebra 2 B

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0
This is even function because
1)the ends are looking in one side, both are up
2)You can see that it has line symmetry y
3) for any point
f(x)=f(-x)
f(1)=-6
f(-1)=-6
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Given the function f(x) = -5x + 11 + 3, for what values of x is f(x) = -12?<br> Bleaseeeeee
Nitella [24]

Answer:

x = 5.2

Step-by-step explanation:

f(x) = -5x + 11 + 3

Let's first simplify our first function:

f(x) = -5x + 11 + 3\\f(x) = -5x + 14

Now, we just need to set this function equal to our other given function.

f(x) = -5x+14\\f(x) = -12\\-5x + 14 = -12

Now, we can add 12 to both sides:

-5x + 14 + 12 = -12 + 12\\-5x + 26 = 0

Now, add 5x to both sides:

-5x+26 = 0\\26 = 5x\\

Finally, we'll divide both sides by 5:

26/5 = 5x / 5\\5.2 = x\\x = 5.2

Answer: x = 5.2

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3 years ago
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kari74 [83]
Is there a photo? I know the last option is true but I feel like there should be a photo with this
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3 years ago
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What is the missing number placed on the blue dot. Assignment from kahan academy
Gwar [14]

Answer:

the blue dot is at -11 value on the number line.

5 0
2 years ago
A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr
Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N      Mass of the man,(m)= \frac{W}{g} = \frac{748}{9.8} = 76.32 kg

Radius of the pond (r) = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is V_m .

Now using law of conservation of momentum we can find the V_m value.

m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)

Considering V_m_(_f_)=V_m

And initial velocity of both the man and book i.e V_b_(_i_)=0,\ V_m_(i_)=0

So,

⇒ 0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m

⇒ Plugging the values.

⇒ V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}

⇒ V_m=-\frac{1.2\times 4}{76.32}

⇒ V_m=-0.062 ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, V_m = 0.062

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know velocity(v)\times time(t) = distance(d)

Let the time taken be t and v\times t = d and d=r then, V_m\times t=r

Then

⇒ t=\frac{radius\ (r)}{V_m}

⇒ Plugging the values.

⇒ t=\frac{4}{0.062}

⇒ t =64 sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0
2 years ago
Anyone please help me check these answers? I'm stressing out and in a panic mode because I may not finish 9th grade. Please help
anygoal [31]
Pic 1 is correct
Pic 2 is correct
Pic 3 is correct
4 0
3 years ago
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