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DIA [1.3K]
3 years ago
7

a bag of 13 marbles contains 2 greeb, 7 blue, 1 yellow, and 3 red marbles. if a blue marble is oulled at random and not put back

, give the probability that the second marble will be yellow
Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0
13 /26. I think is your answer
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Peter saved up $20,000 in an account earning a nominal 5% per year compounded continuously. How much was in the account at the e
kykrilka [37]

Answer:

$22,050

Step-by-step explanation:

$20,000+5%=$21,000

$21,000+5%=$22,050

3 0
3 years ago
WILL GIVE BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!
natali 33 [55]

The answer is C) A triangle with three equal sides because that’s the only one that makes sense.

5 0
3 years ago
Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably infinite, exhib
anzhelika [568]

Answer:

a) Countably infinite

b) Countably infinite

c) Finite

d) Uncountable

e) Countably infinite

Step-by-step explanation:

a) Let S the set of integers grater than 10.

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(10+k)=k-1 for k\in\mathbb{Z}^+/\{0\}.

Let's see that the function is one-to-one.

Suppose that f(10+k)=f(10+j) for k≠j. Then k-1=j-1. Thus k-j=1-1=0. Then k=j. This implies that 10+k=10+j. Then the correspondence is injective.

b) Let S the set of odd negative integers

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(-(2k+1))=k.

Let's see that the function is one-to-one.

Suppose that f(-(2k+1))=f(-(2j+1)) for k≠j. By definition, k=j. This implies that the correspondence is injective.

c) The integers with absolute value less than 1,000,000 are in the intervals A=(-1.000.000, 0) B=[0, 1.000.000). Then there is 998.000 integers in A that satisfies the condition and 999.000 integers in B that satifies the condition.

d) The set of real number between 0 and 2 is the interval (0,2) and you can prove that the interval (0,2) is equipotent to the reals. Then the set is uncountable.

e) Let S the set A×Z+ where A={2,3}

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(2,k)=2k, \;f(3,j)= 2j+1

Let's see that the function is one-to-one.

Consider three cases:

1. f(2,k)=f(2,j), then 2k=2j, thus k=j.

2. f(3,k)=f(3,j), then 2k+1=2j+1, then 2k=2j, thus k=j.

3.  f(2,k)=f(3,j), then 2k=2j+1. But this is impossible because 2k is an even number and 2j+1 is an odd number.

Then we conclude that the correspondence is one-to-one.

6 0
3 years ago
A tractor costs $15,450 and depreciates in value by 14% per year how much will the tractor be worth after 3 years
____ [38]

Answer:

$8,961 is your answer.

Step-by-step explanation:

What you do is multiply.

<em>15,450 x 14% = 2,163</em>

<em>2,163 x 3 = $6,489</em>

<em>$15,450 - $6,489 = $8,961</em>

$8,961 is your answer.

8 0
3 years ago
Read 2 more answers
Expand (2a +36) (2a-3b​
kkurt [141]

Answer:

A jewellery shop is having a sale.

A bracelet is reduced to £240.

a) What is the original price?

A ring is reduced to £840.

This is 40% of the original price.

b) Work out the original price of this ring.A jewellery shop is having a sale.

A bracelet is reduced to £240.

a) What is the original price?

A ring is reduced to £840.

This is 40% of the original price.

b) Work out the original price of this ring.A jewellery shop is having a sale.

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a) What is the original price?

A ring is reduced to £840.

This is 40% of the original price.

b) Work out the original price of this ring.A jewellery shop is having a sale.

A bracelet is reduced to £240.

a) What is the original price?

A ring is reduced to £840.

This is 40% of the original price.

b) Work out the original price of this ring.sjlkajhdjhsjdahd;ahdishoihcuwes xd ad

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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