Answer:
93.32% probability of obtaining a value less than or equal to -7.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the likelihood of obtaining a value less than or equal to -7?
This is the pvalue of Z when X = -7.
So




has a pvalue of 0.9332.
So there is a 93.32% probability of obtaining a value less than or equal to -7.
Answer:
-7
Step-by-step explanation:
Answer:
19.24 weeks
Step-by-step explanation:
Given that;
Mean, m = 18
Standard deviation, s = 3
Break down cost = 2000
Preventive maintenance cost = 1400
The optimal preventive maintenance level is Given by :
Mean + service level * standard deviation
Service level = preventive maintenance cost / (breakdown cost + preventive maintenance cost)
Hence,
Service level = 1400/(1400+2000) = 1400 / 3400
Service level = 0.4117647
Optimal preventive maintenance level :
18 + (0.4117647 * 3)
18 + 1.2352941
= 19.235
= 19.24 weeks
17/100 is the same as 17÷100. 17÷100 =0.17 sqr mile.
OR 17/100, the denominator means what place it is in. The denominator is100, so it's in the hundredth place. 0.17