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zhuklara [117]
3 years ago
10

Which is the best estimate of (Negative three-fifths) (17 and StartFraction 5 over 6 EndFraction)?

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0

Answer:

B is the correct answer

Step-by-step explanation:

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Amy and her sister are making lemonade for the school dance. Their recipe makes 2 quarts of lemonade. If they make 35 times the
horrorfan [7]
There are 4 quarts in a gallon, so do the following:

35 * 2 + 70, 70 / 2 = 35

The answer is B.
5 0
3 years ago
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The weights (in ounces) of 14 different apples are shown below. Find Q 3. 5.7 5.5 4.7 4.4 6.8 5.7 5.5 6.9 6.0 4.4 5.7 6.9 4.4 4.
elena55 [62]
I Think 5.7 I’m Not Sure
6 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
How to plot (3,-3) on a graph?
netineya [11]
They y-axis represents the -3 now all that you need to do is line it up to -3 and 3 in the graph
7 0
3 years ago
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F(x)= StartRoot negative x EndRoot?
Leya [2.2K]

Answer:

f(x) = √-x

Step-by-step explanation:

f(x) = √-x

Step 1: Obtain the value of x (start)

Step 2: The square root  of  -x

Step 3: Write down the value of f(x) (End)

7 0
3 years ago
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