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Soloha48 [4]
3 years ago
10

What is the prime factorization of 585?

Mathematics
2 answers:
meriva3 years ago
7 0

The prime factorization is 3 x 3 x 5 x 13

kodGreya [7K]3 years ago
7 0

Answer:

3x^{2} * 5* 13 in another words:  3 to the power of 2 * 5 *13 as you answer.

Step-by-step explanation:

585:

3 to the power of 2 * 5 * 13

* Hope this helps!! :) Mark Me the Brainliest :)

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EMERGENCY <br> i+i+i+i=-8<br> i=
Anon25 [30]

Answer

<em>i</em><em>=</em><em>2</em>

Step-by-step explanation:

i+i+i+i=8

4i=8

i=8/4

i=2

4 0
3 years ago
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please help i will award brainliest!!!! AB , CD and EF are straight lines intersecting at point O. Find m∠AOC, m∠BOF, m∠COF, m∠C
soldi70 [24.7K]

Answer:

in the attachement below

In the pic3 you can calculate "x" from the equation:

x+15^0+37^0+15^0+37^0+x=360^0




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3 years ago
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What is the best estimate for the percent equivalent of 7/15
Sloan [31]
It is 46.6666667% 7/15=0.466666667 put into a percent it's 46.6666667%
6 0
3 years ago
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What is the area of a hexagon with a side length of 10? it also has a rectangle in it with other measurements but the question i
Anastaziya [24]

Answer:

there is a formula for a hexagon ..  it's

Area = 3\sqrt{3\\}/2 * length^{2}

where length is the length of one side, assuming all sides are equal

Step-by-step explanation:

3*\sqrt{3}/2= 7.348469228.........

since the length is 10...   the length squared is 100

then the total area of the hexagon is 734.8469228...... units^{2}.. what ever they are

if you want to work with some concepts.. you could also say that a hexagon is just a box with the corners cut off and the triangles that are missing are the equilateral right triangles with a hypotenuse of 10 .  and since 2 pieces of those triangles make a square.. you can subtract two squares of that size from the bigger box that the hexagon fits into.  this is a long way to figure this out but might be good for trigonometry practice   :)

it will also be 734.8463288.....  see if you can work that out :)

6 0
3 years ago
A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at a rate of 10
just olya [345]

Answer:

\frac{dh}{dt}≅0.286\frac{ft^{3} }{min}

Step-by-step explanation:

V=\frac{\pi }{3}r^{2}h; rate of change \frac{dV}{dt}=10\frac{ft^{3} }{min}, we must find the rate of change of the depth \frac{dh}{dt} =?;h=8ft

5h=12r; V=\frac{\pi }{3}\({\((5h}/12} )} ^{2}h=\frac{\pi }{3}(\frac{25h^{2} }{144})h; V=\frac{25\pi h^{3}}{432}; deriving \frac{dV}{dt} = \frac{25\pi }{432}(3h^{2})\frac{dh}{dt} → 10=\frac{25\pi h^{2}}{144} \frac{dh}{dt} → h=8 then \frac{dh}{dt}=\frac{1440}{25\pi 64}=\frac{9}{10\pi}≅ 0.286\frac{ft^{3} }{min}

3 0
4 years ago
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